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Anastaziya [24]
4 years ago
6

1 Verify the identity. Show your work. cot θ ∙ sec θ = csc θ

Physics
1 answer:
Fittoniya [83]4 years ago
6 0
To verify the identity, we can make use of the basic trigonometric identities:
cot θ = cos θ / sin θ 
sec θ = 1 / cos <span>θ
csc </span>θ = 1 / sin θ<span>

Using these identities:
</span>cot θ ∙ sec θ = (cos θ / sin θ ) (<span> 1 / cos </span><span>θ)
</span>
We can cancel out cos <span>θ, leaving us with
</span>cot θ ∙ sec θ = 1 / sin θ
cot θ ∙ sec θ = = csc <span>θ</span>
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1. Definition of a family

A family is a group of people living together in a home related by blood, marriage or adoption.

2. Two function of the family are;

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3. Two types of family are;

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4. Two roles and responsibilities of the parents and children in the home are;

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<u>Accident in the Home</u>

1. Definition of accident in the home

accidents in the home are common to persons of all ages, therefore home accidents occurs in one's home that may cause an result an injury of a person

2. Two types of accident in the home

  1. falls
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3. The two uses of cereals in cooking

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4. complete table

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A 3.00 kg block moving 2.09 m/s
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How are mountain ecosystems different from other ecosystems?
Andreyy89

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They host three or more distinct ecosystems at different elevations.

Explanation:

I checked it, and its right.

3 0
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A magnetic compass is placed near an insulated copper wire. When the wire is connected to a battery and a current is created, th
Luba_88 [7]
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Every current through a wire produced a magnetic field. And since the magnetic field of Earth is weak, it will get attracted towards the wire.
4 0
3 years ago
Read 2 more answers
Imagine two billiard balls on a pool table. Ball A has a mass of 7 kilograms and ball B has a mass of 2 kilograms. The initial v
wlad13 [49]
1) In a perfectly inelastic collision, the two balls stick together after the collision. In this type of collision, the total kinetic energy of the system is not conserved, while the total momentum is conserved.
If we callv_f the final velocity of the two balls that stick together, the conservation of the total momentum before and after the collision can be written as
m_a v_{Ai} + m_b v_{Bi} = (m_A+m_B)v_f (1)
where
m_A=7 kg is the mass of ball A
m_B=2 kg is the mass of ball B
v_{Ai}=6 m/s is the initial velocity of ball A
v_{Bi}=-12 m/s is the initial velocity of ball B (taken with a negative sign, since it goes in the opposite direction of ball A)

If we solve (1) to find v_f, we find that the final velocity of the balls is
v_f= \frac{m_Av_{Ai}+m_Bv_{Bi}}{m_A+m_B}= \frac{(7\cdot 6)+(2 \cdot (- 12))}{7+2}= \frac{18}{9}=2 m/s
and the positive sign means the two balls are going to the right.


2) I assume here we are talking about an elastic collision. In this case, both total momentum and total kinetic energy are conserved:
m_A v_{Ai}+m_B v_{Bi} = m_A v_{fA} + m_B v_{fB}
\frac{1}{2}m_A v_{Ai}^2+ \frac{1}{2}m_B v_{Bi}^2= \frac{1}{2}m_Av_{fA}^2+ \frac{1}{2}m_B v_{fB}^2
where
v_{fA} is the final velocity of ball A
v_{fB} is the final velocity of ball B

If we solve simultaneously the two equations, we find:
v_{fA}= \frac{v_{Ai}(m_A-m_B)+2m_Bv_{Bi}}{m_A+m_B} = \frac{(6)(7-2)+2(2)(-12)}{7+2}=-2 m/s
v_{fB}= \frac{v_{Bi}(m_B-m_A)+2m_Av_{Ai}}{m_A+m_B} = \frac{(-12)(2-7)+2(7)(6)}{7+2}= \frac{144}{9}=16 m/s
So, after the collision, ball A moves to the left with velocity v=-2 m/s and ball B moves to the right with velocity v=16 m/s.

3) The total momentum before and after the collision is conserved.
In fact, the total momentum before the collision is:
p_i = m_A v_{A} + m_B v_{fB} = (7\cdot 6)+(2 \cdot (-12))=42-24=18 m/s
and the total momentum after the collision is:
p_f = m_A v_{A} + m_B v_{fB} = (7\cdot (-2))+(2 \cdot 16)=-14+32=18 m/s

3 0
3 years ago
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