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Citrus2011 [14]
3 years ago
5

Plzzzz helppppppppppp

Physics
1 answer:
pashok25 [27]3 years ago
7 0

1. Explain, using Kinetic theory, why when you have a hot room, the room cools down when you open a window to the cold outside.

Answer:

According to kinetic theory of gases, at higher temperature, the molecules in air have higher kinetic energy and they are moving at a faster speed. Hence the pressure is greater. And Air moves from higher pressure to lower pressure.

In a hot room, the air pressure is greater. The cool air outside has lower pressure. On opening the window, Air moves from higher pressure to lower pressure, from outside to inside.

2. If an atom is 1*10^(-10) m wide, and the nucleus is 1*10^(-15) m wide, how wide would the atom be if the nucleus was scaled up to be 1 cm wide?

Answer:

When nucleus was scaled upto 1 cm, atom would be 10^(5) cm.

The question is pretty simple, we just have to scale the size of nucleus to larger value and get the size of atom accordingly.

We know that

when nucleus is 10^(-15) m => atom is 10^(-10) m

When nucleus becomes 1 m => atom is 10^(-10) * 10^(15) m = 10^(5) m

When nucleus is 1 * 10^(-2) => atom is 10^(5) * 10^(-2) m

When nucleus is 1 cm => atom is 10^(5) cm

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Answer:

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Explanation:

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One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side
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Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

L1^2=L2^2=L^2=2^2+(H/2)^2  Replacing this value in the previous equation:

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H=\sqrt{52}

We can now, calculate the angle between L1 and the 2m segment:

\alpha = atan(\frac{H/2}{2})=60.98°

If we make a sum of forces in the midpoint of the rope we get:

-2*T*cos(\alpha ) + F = 0  where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N

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