The chairlift at a ski resort has a vertical rise of 3200 feet. if the length of the ride is 1.2 miles, what is the average angl
e of elevation of the lift (to the nearest tenth of a degree)?
1 answer:
(see attached graphic)
1.2 miles = 6,336 feet
IF the length is measured along the ground then:
tan (angle) = opp / adjacent
tan (angle) = 3,200 / 6,336
<span>tan (angle) = 0.505050505</span>
angle = 26.796 Degrees
IF the length is measured from the ground to the top then:
sin (angle) = opp / hypotenuse
<span>sin (angle) = 0.505050505</span>
angle = 30.335 Degrees
1.2 miles = 6,336 feet
IF the length is measured along the ground then:
tan (angle) = opp / adjacent
tan (angle) = 3,200 / 6,336
<span>tan (angle) = 0.505050505</span>
angle = 26.796 Degrees
IF the length is measured from the ground to the top then:
sin (angle) = opp / hypotenuse
<span>sin (angle) = 0.505050505</span>
angle = 30.335 Degrees
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