If their mean is 5, then the numbers add up to 25.
Here are a few sets that do the job:
1, 2, 3, 4, 15
10, 20, 30, 40, -75
+2, -2, +99, -99, 25
1, 5, 5, 5, 9
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
The correct answer is letter D, Region D contains the solution for the system of inequalities.
Answer:
440
Step-by-step explanation:
3 hundreds= 300
13 tens= 130
10 ones=10
300+130+10=440
