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3 years ago

As light shines from air to water (n = 1.33) at an incident angle of 45.0 degrees what is the angle of refraction

1 answer:

5 0

Using Snell's law
we get
sin(I)/sin(r) = U2/U1
• where U2 represent the water's refractive index and U1 represent air's refractive index
thus
sin45°sin(r) = 1.33/1
1/√2*1.33 = sin(r)
1/1.88 = sin(r)
0.531 = sin(r)
thus the refractive angle is 32°

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2 years ago

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Answer:

time of collision is

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Explanation:

initial speed of the ball when it is dropped down is

$v_1 = 0$

similarly initial speed of the object which is projected by spring is given as

$v_2 = 16.2 m/s$

now relative velocity of object with respect to ball

$v_r = 16.2 m/s$

now since we know that both are moving under gravity so their relative acceleration is ZERO and the relative distance between them is 6.4 m

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Now the height attained by the object in the same time is given as

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$h = 16.2(0.395) - \frac{1}{2}(9.81).395^2$

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4 years ago

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nasty-shy [4]

Answer:

True

Explanation:

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3 years ago

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3 years ago

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3 years ago

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