second question: How many seconds after the first snowball
should you throw the second so that they
arrive on target at the same time?
Answer in units of s.
Answer:
Part 1: 28°
Part 2: 1.367
Explanation:
Part 1:
Given: 62°
Simple
θ = 90°- 62°
<u>θ = 28°</u>
Part 2:
Y-direction
Δy
![t_{1} =\frac{2[16.2sin(62)]}{9.8}](https://tex.z-dn.net/?f=t_%7B1%7D%20%3D%5Cfrac%7B2%5B16.2sin%2862%29%5D%7D%7B9.8%7D)

![0=[16.2sin(28)]t_{2}+1/2(-9.8)t_{2}^{2}](https://tex.z-dn.net/?f=0%3D%5B16.2sin%2828%29%5Dt_%7B2%7D%2B1%2F2%28-9.8%29t_%7B2%7D%5E%7B2%7D)
![t_{2} =\frac{2[16.2sin(28)]}{9.8}](https://tex.z-dn.net/?f=t_%7B2%7D%20%3D%5Cfrac%7B2%5B16.2sin%2828%29%5D%7D%7B9.8%7D)

Δt
Δt
<u>Δt= 1.367s</u>
Hope it helps :)
Answer:
25 N; 250 W.
Explanation: Work Done
=
Force
×
Displacement
×
cos
(
The angle between Force and Displacement
)
So, Let's Assume the Force to be
x
Newtons.
So, According to The Sum,
×
x
x
⋅
100
=
2500
⇒
x
=
25
00
1
00
=
25
So, The force was
25
N
.
And, We also know,
Power
=
Work Done
Time
So,
The Power of the Machine =
2500
10
Watts
=
250
Watts
Always here to help. Bring it!!!
Answer:
≈ 4.41 x 10^-19
Explanation:
The formula for the energy of light is...
E = hc / λ
where 'h' is Planck's constant: 6.626 x 10^-34 Js
'c' is the speed of light: 2.998 x 10^8 ms
& 'λ' is the wavelength (in this case): 450 nm
1 nanometer (nm) = 1 x 10^-9m
E = (6.626 x 10^-34 Js)(2.998 x 10^8 ms) / (450nm)(1 m / 10^-9 nm)
E ≈ 4.41 x 10^-19 J
I think that's the answer and I hope it helps!