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Komok [63]
3 years ago
11

Plz help i need answers to all these questions

Physics
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:

1) The net force is 5 N. The box is accelerating 10 m/s

2)  The net force is 6.986 N. It is accelerating. Normal Force is 16.986

Explanation:

1) 20 N forward - 15 N backwards = a net force of 5 N

  Acceleration: Acceleration = Net Force * Mass ( derived from Force = mass * acceleration).

a = 5 N / 2 kg

a= 2.5 m/s^2

2)

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<h3>What are arc-fault circuit interrupter?</h3>

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1 year ago
I shared a picture of the problem. It’s a basic Physics question and an Algebra question.
julia-pushkina [17]

Hence the expression of ω in terms of m and k is

\omega = \sqrt{\frac{k}{m}

Given the expressions;

T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}

Equating both expressions we will have;

2 \pi \sqrt{\frac{m}{k} }  = \frac{2 \pi}{\omega}

Divide both equations by 2π

\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\

Square both sides

(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}

Take the square root of both sides

\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}

Hence the expression of ω in terms of m and k is

\omega = \sqrt{\frac{k}{m}

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Which describes Newton's law of universal gravitation?
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