Which graph BEST represents the motion of a car that runs out of gas on while driving along a flat highway?
2 answers:
Hey there!
So, when reviewing this question, we would want to find a graph that would start fresh and end back down.
This would mean that, the car would have to first start the car, accelerate, and then go on the highway, and then (sadly), he run's out of gas.
For example, if I were to run a race, I would have to start, which mean's that I would start on the bottom of the graph, and then when I keep running, the line would get higher and higher, but then (when I run out of breath) and will then slow down, and eventually stop.
So, it's the same in this case, the car was driving at a constant speed, and then ran out of gas, and then the car would have to turn off. This mean's once again that the graph line would have to start low, and end low.
From your option's listed above, the graph that I see that does this would be (graph A). It start's low, and end's low. B would <em>NOT </em> be the answer because the line stay's straight going up the whole time. C would <em>NOT </em> be the answer because he started high, and ended low.
This would be tricky. You can not start high and end low. When I did that race, I didn't start going 5 (mph) fast. I slowly got up there. And (for the last option) D, D would <em>NOT </em>be your answer because he did not start like that.
Your correct answer would be . . .
Hope this helps.
~Jurgen
So, when reviewing this question, we would want to find a graph that would start fresh and end back down.
This would mean that, the car would have to first start the car, accelerate, and then go on the highway, and then (sadly), he run's out of gas.
For example, if I were to run a race, I would have to start, which mean's that I would start on the bottom of the graph, and then when I keep running, the line would get higher and higher, but then (when I run out of breath) and will then slow down, and eventually stop.
So, it's the same in this case, the car was driving at a constant speed, and then ran out of gas, and then the car would have to turn off. This mean's once again that the graph line would have to start low, and end low.
From your option's listed above, the graph that I see that does this would be (graph A). It start's low, and end's low. B would <em>NOT </em> be the answer because the line stay's straight going up the whole time. C would <em>NOT </em> be the answer because he started high, and ended low.
This would be tricky. You can not start high and end low. When I did that race, I didn't start going 5 (mph) fast. I slowly got up there. And (for the last option) D, D would <em>NOT </em>be your answer because he did not start like that.
Your correct answer would be . . .
Hope this helps.
~Jurgen
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Answer:
Explanation:
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But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.