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Alexxandr [17]
3 years ago
13

the perimeter of a rectangle is 62 meters. if the width were doubled and the length were increased by 21 meters, the perimeter w

ould be 120 meters. what are the length and width of the original rectangle?
Mathematics
1 answer:
iren [92.7K]3 years ago
6 0
62=2w+2l
120= 2(2w)+ 2(l+21)

120=4w+2l+42
78= 4w+2l
39=2w+l
39-2w=l

Use substitution
62=2w+2(39-2w)
62= 2w+78-4w
62= -2w+78
-16=-2w
8=w

Plug w in
62=2(8)+2l
62=16+2l
46=2l
23=l

Final answer: Width=8, Length=23
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True [87]
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Temka [501]
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