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3 years ago

Compare. Write <, >, or=.11. V8 +3( ) 8+ V3

Mathematics

1 answer:

Levart [38]3 years ago

8 0

Answer:

Step-by-step explanation:

v8 + 3 = 8 + v3

-3 -3

________________

v8 = 5 + v3

-v3 -v3

___________

v5 = 5

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If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

3 years ago

The management of an electronics firm has determined that the profit the company earns is a function of thenumber of employees i

ruslelena [56]

we have the function

$P(x)=\ln\left|4x+1\right|+3x-x^2$

For x=2

substitute

$\begin{gathered} P(x)=\operatorname{\ln}\lvert4(2)+1\rvert+3(2)-(2)^2 \\ P(x)=\operatorname{\ln}\lvert9\rvert+2 \\ P(x)=4.20\text{ millions of dollars} \end{gathered}$

therefore

<h2>the answer is 4.20 million dollars</h2>

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1 year ago

Compare. Write <, >, or=.11. V8 +3( ) 8+ V3​

Compare. Write <, >, or=.11. V8 +3( ) 8+ V3