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zheka24 [161]
3 years ago
8

Write anwsers as fractions using / as fraction bar and write the greater value first

Mathematics
1 answer:
puteri [66]3 years ago
6 0

Answer:

Final answer is \frac{3}{2} or \frac{1}{2}.

Step-by-step explanation:

Given equation is \log_x\left(8x-3\right)-\log_x\left(4\right)=2

Now we need to solve that equation for x.

\log_x\left(8x-3\right)-\log_x\left(4\right)=2

Apply formula \log_c\left(A\right)-\log_c\left(B\right)=\log_c\left(\frac{A}{B}\right)

\log_x\left(\frac{8x-3}{4}\right)=2

Apply formula \log_c\left(A\right)=b \Rightarrow c^b=A

x^2=\frac{8x-3}{4}

4x^2=8x-3

4x^2-8x+3=0

4x^2-2x-6x+3=0

2x(2x-1)-3(2x-1)=0

(2x-3)(2x-1)=0

2x-3=0 or 2x-1=0

2x=3 or 2x=1

x=\frac{3}{2} or x=\frac{1}{2}

Hence final answer is \frac{3}{2} or \frac{1}{2}.

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Ted is correct. Maggie made mistakes while trying to isolate x for both equations.

Step-by-step explanation:

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3 years ago
The play director spent 190190190 hours preparing for a play. That time included attending 353535 rehearsals that took varying a
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Answer:

The equation 35x+93\frac{3}{4} =190 gives average time spent on 35 rehearsals.

Step-by-step explanation:

We are supposed to find that what question does the equation 35x+93\frac{3}{4} =190 finds answer of.

We can see that 35x represents time spent on 35 rehearsals and 93\frac{3}{4} is time spent on other responsibilities related to play. The sum of these times equals to total time spent on preparing the play.

Now let us solve our equation step by step.

35x+\frac{375}{4} =190

After subtracting 93\frac{3}{4} hours from 190 hours we will get time spent on 35 rehearsals.

35x =190-\frac{375}{4}

35x =\frac{760-375}{4}

35x =\frac{385}{4}

Time spent on 35 rehearsals is 96.25 hours and we are told that each rehearsal took different amount of time. Dividing 96.25 by 35 we will get average time spent on each rehearsal.

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Therefore, equation 35x+93\frac{3}{4} =190 finds average time spent on 35 rehearsals.


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