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zheka24 [161]
4 years ago
8

Write anwsers as fractions using / as fraction bar and write the greater value first

Mathematics
1 answer:
puteri [66]4 years ago
6 0

Answer:

Final answer is \frac{3}{2} or \frac{1}{2}.

Step-by-step explanation:

Given equation is \log_x\left(8x-3\right)-\log_x\left(4\right)=2

Now we need to solve that equation for x.

\log_x\left(8x-3\right)-\log_x\left(4\right)=2

Apply formula \log_c\left(A\right)-\log_c\left(B\right)=\log_c\left(\frac{A}{B}\right)

\log_x\left(\frac{8x-3}{4}\right)=2

Apply formula \log_c\left(A\right)=b \Rightarrow c^b=A

x^2=\frac{8x-3}{4}

4x^2=8x-3

4x^2-8x+3=0

4x^2-2x-6x+3=0

2x(2x-1)-3(2x-1)=0

(2x-3)(2x-1)=0

2x-3=0 or 2x-1=0

2x=3 or 2x=1

x=\frac{3}{2} or x=\frac{1}{2}

Hence final answer is \frac{3}{2} or \frac{1}{2}.

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Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer

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