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4 years ago

If A+B+C=180 prove that cos^2a + cos^2B + cos^2C = 1 - 2COSACOSBCOSC

Mathematics

1 answer:

IceJOKER [234]4 years ago

4 0

Please read the attached file

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Suppose a force of 30 N is required to stretch and hold a spring 0.1 m from its equilibrium position. a. Assuming the spring obe

AlexFokin [52]

Answer:

a) $k = 300\,\frac{N}{m}$ , b) $\Delta U_{k} = 13.5\,J$ , c) $\Delta U_{k} = 6\,J$ , d) $\Delta U_{k} = 4.5\,J$

Step-by-step explanation:

a) The spring constant is calculated by using this expression:

$k = \frac{F}{x}$

$k = \frac{30\,N}{0.1\,m}$

$k = 300\,\frac{N}{m}$

b) The work needed to compress the spring from its initial position is:

$\Delta U_{k} = \frac{1}{2}\cdot k \cdot (x_{f}^{2}-x_{o}^{2})$

$\Delta U_{k} = \frac{1}{2}\cdot (300\,\frac{N}{m} )\cdot [(-0.3\,m)^{2}-(0\,m)^{2}]$

$\Delta U_{k} = 13.5\,J$

c) The work needed to stretch the spring is:

$\Delta U_{k} = \frac{1}{2}\cdot (300\,\frac{N}{m} )\cdot [(0.2\,m)^{2}-(0\,m)^{2}]$

$\Delta U_{k} = 6\,J$

d) The work need to stretch the spring is:

$\Delta U_{k} = \frac{1}{2}\cdot (300\,\frac{N}{m} )\cdot [(0.2\,m)^{2}-(0.1\,m)^{2}]$

$\Delta U_{k} = 4.5\,J$

8 0

4 years ago

Read 2 more answers

The point (0, –4) is located on _____ .

maria [59]

Answer:

On The Y axis

Step-by-step explanation:

it labeled as (x,y) so i goes down -4 and so it is on the y axis

mark brainliest

3 0

3 years ago

Solve each equation using the quadratic formula. Find the exact solution, then approximate the solution to the nearest hundredth

Anika [276]

Answer:

$x_1=\frac{5+\sqrt{33}}{4}$ ≈2.69

$x_2=\frac{5-\sqrt{33}}{4}$ ≈-0.19

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You have that the quadratic formula is:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

2. To solve the quadratic equation you must substitute the values. So, you have that:

Rewrite the equation:

$2x^{2}-5x-1=0$

$a=2\\b=-5\\c=-1$

Then you have:

$x=\frac{-(-5)+/-\sqrt{(-5)^{2}-4(2)(-1)}}{2(2)}$

3. Therefore, you obtain the following result:

$x_1=\frac{5+\sqrt{33}}{4}$ ≈2.69

$x_2=\frac{5-\sqrt{33}}{4}$ ≈-0.19

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3 years ago

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HURRY PLEASE WILL GIVE BRAINLIEST

BigorU [14]

Answer:

graph c

Step-by-step explanation:

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3 years ago

In order to inscribe a circle in a triangle, which line must you construct?

Andre45 [30]

<span>D) Angle Bisector => incenter </span>

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3 years ago