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3 years ago

Which of the following fractions can be represented by a terminating decimal? A. 8/9 B. 13/8 C. 4/3 D. 6/11

Mathematics

2 answers:

wel3 years ago

8 0

Answer:

B. 13/8.

Step-by-step explanation:

1/9 = 0.111...... so 8/9 is not one

1/8 = 0.125 so its 13/8.

4/3 is not one as 1/3 = 0.33....

1/11 = 0.090909.... so its not 6/11.

goblinko [34]3 years ago

4 0

Answer:

Step-by-step explanation:

13/8 because when simplified into a decimal would be 1.625 and if you round would be 2 so you take out the decimal

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3 years ago

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ASAP The tee for the fourth hole on a golf course is 300 yards from the tee. On that hole, Marsha hooked her ball to the left, a

andrey2020 [161]

Answer:

C. 97.5 yd

Step-by-step explanation:

The distance between Marsha, the ball and the tee for the fourth hole, forms a triangle.

Thus, the distance between Marsha's ball and the hole can be calculated using the Cosine formula below:

c² = a² + b² - 2abcos(C)

Where,

c = distance between Marsha's ball and the hole = ?

a = distance between the tee for the fourth hole and the tee = 300 yd

b = distance between tee and the hole = 255 yd

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2 years ago

Answer each of the questions for the following diagram:

sweet [91]

Answer:

1. Complimentary angles

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3 years ago

Un jardín rectangular de 50 cm de largo por 34 m de ancho está rodeado por un camino de arena uniforme.Halla la anchura de dicho

Anastasy [175]

Answer:

5.85 m

Step-by-step explanation:

The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:

$A_{g} = a.b$

<u>Where:</u>

Ag: is the area of the rectangular garden

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b: is the width of the rectangular garden = 34 m

$A_{s} = 540 m^{2}$

<u>Where</u>:

As: is the area of the sand road

The relation between the area of the sand road and the area of the rectangular garden is the following:

$A_{s} + A_{g} = (a+2x)*(b+2x)$

$540 m^{2} + 0.5m*34m = ab + 2ax + 2bx + 4x^{2}$

$557 m^{2} = ab + 2x(a + b) + 4x^{2}$

$557 m^{2} - 17m^{2} - 2x(34.5 m) - 4x^{2} = 0$

$540 - 69x - 4x^{2} = 0$

By solving the above equation for x we have two solutions:

x₁ = -23.10 m

x₂ = 5.85 m

Taking the positive value, we have that the width of the sand road is 5.85 m.

I hope it helps you!

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