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3 years ago

8

HEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPP WITH ANSWER PLZZZZ

2 answers:

antiseptic1488 [7]3 years ago

6 0

78 units squared add together 27.5+12+22+16.5 and you’ll get your answer for triangles it’s 1/2bh and for the rectangles it’s just bh. hope this helped!

Yakvenalex [24]3 years ago

4 0

Answer:

78 hope this helps

Step-by-step explanation:

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The difference of two perfect cubes is 386. If the cube root of the smaller of the two numbers is 7, then the cube root of the l

choli [55]

Answer:

9

Step-by-step explanation:

Let the two perfect cubes be x and y where x > y.

According to the given conditions:

${x}^{3} - {y}^{3} = 386...(1) \\ y = 7...(2) \\ plug \: y = 7 \: in \: equation \: (1) \\ {x}^{3} - {7}^{3} = 386 \\ {x}^{3} - 343 = 386 \\ {x}^{3} = 343 + 386 \\ {x}^{3} = 343 + 386 \\ {x}^{3} = 729 \\ x = \sqrt[3]{729} \\ x = 9$

Thus the cube root of the larger number is 9.

8 0

3 years ago

A cell phone tower is anchored by two cables on each side for support. The cables stretch from the top of the tower to the groun

kramer

Answer:

659.6 ft

Step-by-step explanation:

x = 140 / tan 23

x = 329.82(rounded to hundredth)

so total ground distance between the cables = 2x = 2(329.82) = 659.64 feet

4 0

2 years ago

Tcecarenko [31]

Answer:

The COP is 0.5

Step-by-step explanation:

First we must find the slopes.

12.50/25 = 0.5

17.50/35 = 0.5

The COP is 0.5

8 0

3 years ago

A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

Hence The width of the sandbox is $42\frac{2}{3} \ ft$ .

5 0

3 years ago

Ann and Betty shared a sum of money in the ratio 2:3 Ann received $120 what was Betty's share

const2013 [10]

Set up a proportion

2/3= 120/x

2*60=120
3*60=180
x=180

Final answer: $180

3 0

3 years ago

Read 2 more answers