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2 years ago

PLSSSS HELP D: (85 points + brainliest)

Mathematics

1 answer:

irga5000 [103]2 years ago

5 0

I’ve asked my teacher for the same thing and all he said was that this wasn’t possible! I still to this day wonder if he knew the answer!! Sorry tho I couldn’t help!

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Mai poured `2.6` liters of water into a partially-filled pitcher. The pitcher now contains `10.4` liters. Mai wants to know how

prisoha [69]

Answer: 7.8

Step-by-step explanation: If we want to find the amount that was in the pitcher before then we subtract 2.6 from 10.4 to find the original amount because if the pitcher were to contain an amount that only adds up to 10.4 before we add 2.6 then the number that adds with 2.6 to equal 10.4 is our answer

hence our answer 7.8

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2 years ago

Read 2 more answers

Written equation for y=-2=1 (0,3)

Alika [10]

Is that supposed to be y=-2x+1?
i cannot solve without the proper equation lol

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3 years ago

What are the amplitude, period, and phase shift of the given function? f(t)=-1/2sin(3t-2pi)

Romashka [77]

Answer:

The $amplitude=|A|=\frac{1}{2}$ , $period=3$ and $\text{phase shift}=\frac{2\pi}{3}$ .

Step-by-step explanation:

The given function is

$f(t)=-\frac{1}{2}\sin (3t-2\pi)$ .... (1)

The general form of sine function is

$F(t)=A\sin (Bt-C)+D$ ....(2)

where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.

On comparing (1) and (2), we get

$A=-\frac{1}{2}$

$B=3$

$C=2\pi$

$D=0$

So,

$amplitude=|A|=\frac{1}{2}$

$period=3$

$\text{phase shift}=\frac{2\pi}{3}$

Therefore $amplitude=|A|=\frac{1}{2}$ , $period=3$ and $\text{phase shift}=\frac{2\pi}{3}$ .

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3 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.