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3 years ago

Can you help me? Please

Mathematics

1 answer:

aksik [14]3 years ago

4 0

x° = 60° (alternate angle)

Step-by-step explanation:

Hope it helps you!

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If 25% of all students in the 7th grade have pets, and there are 40 students with pets, how many total students are there in the

VashaNatasha [74]

Answer:

there would be 160 as if 25% of the student body is 40 then you would multiply it by 4 to get to 100% of the student body thus giving you 160.

Step-by-step explanation:

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2 years ago

Which expression defines the arithmetic series 4+8+12+... for four terms?

SSSSS [86.1K]

there are 6 terms! hope this helped

4 0

3 years ago

Seven times the sum of 4 and some number is 42

Naddik [55]

Answer:

$x=2$

Step-by-step explanation:

$7\times{(4+x)}=42$

Divide both sides by 7:

$4+x=42\div{7}\\4+x=6$

Subtract 4 from both sides:

$x=6-4\\x=2$

7 0

3 years ago

90 points!!! Algebra - Please check these

Korvikt [17]

First picture:

2 and 7 are alternate exterior angles, which when added together need to equal 180 degrees.

Angle 7 = 180 - 146 = 34

Answer is B.34

Second picture:

Angle 8 = 48

Angle 8 + angle 7 = 180

Angle 7 = 180 - 49 = 131

Angle 5 and angle 7 are vertical angle, so angle 5 = angle 7 = 131

Angle 6 is a vertical angle to angle 8 so = 49

Angle 1 = angle 5 = 131

Angle 2 = angle 6 = 49

Angle 3 = angle 7 = 131

Angle 4 = angle 8 = 49

4 0

3 years ago

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

Read 2 more answers