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adoni [48]
3 years ago
6

O prevent tank rupture during deep-space travel, an engineering team is studying the effect of temperature on gases confined to

small volumes. what is the pressure of 3.40 mol of gas d measured at 251 ∘c in a 1.75-l container assuming ideal behavior?
Physics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

To calculate for the pressure of the system, we need an equation that would  relate the number of moles (n), pressure (P), and temperature (T) with volume (V). There are a number of equations that would relate these values however most are very complex equations. For simplification, we assume the gas is an ideal gas. So, we use PV = nRT.<span>

PV = nRT  where R is the universal gas constant
P = nRT / V</span>

<span>P = 3.40 mol ( 0.08205 L-atm / mol-K ) (251 + 273.15 K) / 1.75 L </span>

<span>P = 83.56 atm</span>

<span>
</span>

<span>Therefore, the pressure of the gas at the given conditions of volume and temperature would be 83.56.</span>

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A spatially challenged goldfish swims along the x-axis only. Its initial position is 7.8 m. After swimming back and forth a whil
Verdich [7]

Answer:

<em>The fish displacement was -3.4 m</em>

Explanation:

<u>Distance and Displacement</u>

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3 0
3 years ago
How much heat is lost by 2.0 grams of water if the temperature drops from 31 °C to 29 °C? The specific heat of water is 4.184 J/
Elanso [62]

Given :

Mass of water, m = 2 grams.

The temperature of water drops from 31 °C to 29 °C .

The specific heat of water is 4.184 J/(g • °C).

To Find :

Amount of heat lost in this process.

Solution :

We know, heat lost is given by :

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Therefore, amount of heat lost in this process is 16.736 J.

4 0
3 years ago
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