Question

two bowling balls, a and b, each having a mass of 7.00 kilograms, are placed 3.00 meters apart. what is the magnitude of the gravitational force exerted by ball a on ball b?

Answer 1

The magnitude of the gravitational force exerted by ball A on ball B is equal to 36.31 × 10⁻¹¹ N.

What is gravitational force?

Newton’s law of gravitation can be defined as every particle of matter in the universe attracting every other particle with mass with a certain force. The magnitude of gravitational force has a direct relationship with their masses.

Therefore, the gravitational force between two bodies can be written as:

$\displaystyle F =G\frac{M_1M_2}{r^2}$

Where G denotes the universal gravitational constant.

Given, the mass of the Ball A = Ball B = 7 Kg

The separation between the two balls, r = 3 m

The magnitude of the gravitational force applied by ball A on ball B can be determined as:

$\displaystyle F =6.67 \times 10^{-11} \times \frac{7\times 7}{(3)^2}$

F = 36.31 × 10⁻¹¹ N

Therefore, the gravitational force is equal to 36.31 × 10⁻¹¹ N.

Learn more about gravitational force, here:

brainly.com/question/12528243

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