Kinetic energy can be calculated using the following rule:
kinetic energy = 0.5*m*v^2 where:
m is the mass = 22 kg
v is the velocity = 3 m/sec
Substitute with the givens in the above equation to get the kinetic energy as follows:
kinetic energy = 0.5(22)(3)^2
kinetic energy = 99 Joules
Momentum
mava + mbvb = mava '+ mbvb'
(300 x 10)+(150 x 0) = (300 x 4.12)+(150 x vb')
3000=1236+150vb'
1764 = 150vb'
vb'=+11.76 m/s ≈ +11.8 m/s (positive sign, to the right)
Answer:
a)
, b)
,
, 
Explanation:
a) The system mass-spring is well described by the following equation of equilibrium:

After some handling in physical and mathematical definition, the following non-homogeneous second-order linear differential equation:
The solution of this equation is:

The velocity function is:

Initial conditions are:

Equations at
are:

The spring constant is:


After some algebraic handling, amplitude and phase angle are found:


The position can be described by this function:

b) The period of the motion is:


The amplitude is:

The phase of the motion is:

C) studying seismic waves
AKA what is studied from earthquakes
Answer:
No
Explanation:
No matter where an object is, its mass will stay the same, but its weight might change depending on gravity.