Answer:
a.(10,23)
b.(7,30)
e.(20,20)
Step-by-step explanation:
We are given that
x=Width of garden
y=Length of garden
According to question


Perimeter of rectangle=
Where x=Width of rectangle
y=Length of rectangle
Fencing used =

First we change inequality into equality
...(1)
...(2)

...(3)
Substitute x=0 in equation (3)

Substitute y=0 in equation (3)

Substitute x=0 and y=0 in equation (3)


It is true. Therefore, the shaded region below the line.


These are false equation .Therefore, the shaded region above the line.
Substitute x=5 in equation (3)


Substitute y=20 in equation (3)


Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).
Now,
a.(10,23)
Substitute in


10>5 and 23>20
it satisfied all inequality.
Hence, it is a solution.
b.(7,30)
7>5
30>20

it satisfied all inequality.
Hence, it is a solution.
c.(18,25)
18>5
25>20

It does not satisfied third inequality
Hence, it is not a solution.
d.(8,35)
8>5
35>20

It does not satisfied third inequality
Hence, it is not a solution.
e.(20,20)

20>5
20=20
it satisfied all inequality.
Hence, it is a solution.