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zlopas [31]
3 years ago
14

Can you find 10/21 of 3/ 10

Mathematics
1 answer:
hoa [83]3 years ago
5 0
<span>0.1428571428 would be the correct answer</span>
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You have $5.00 in quarters and dimes. You have a total of 41 coins. How many of the coins are quarters?
Dmitry_Shevchenko [17]
One because if you put two then the would be 50 and thats over 41
8 0
3 years ago
Simplify the expression below. (2n/6n+4)(3n+2/3n-2)
andrezito [222]

Answer:

\frac{n}{3n-2}

Step-by-step explanation:

Given the expression:

\frac{2n}{(6n+4)} \cdot \frac{3n+2}{3n-2}

Using the distributive property: a \cdot (b+c) =a\cdot b+a\cdot c

\frac{2n}{2(3n+2)} \cdot \frac{3n+2}{3n-2}

Simplify:

\frac{2n}{2} \cdot \frac{1}{3n-2}

Simplify:

\frac{n}{3n-2}

Therefore, the simplified given expression is, \frac{n}{3n-2}

7 0
3 years ago
Read 2 more answers
12% is 90% of what number?
Andrews [41]
12% = 0.12

90% = 0.9

0.12 = 0.9 \times x\\\\x = \frac{0.12}{0.9}=\boxed{1.33333}
7 0
3 years ago
A triangle has two sides of length 20 and 11. What is the largest possible whole-number length for the third side?
charle [14.2K]

Answer:

30

Step-by-step explanation:

20+11=31

It can't be exactly 31 but it can be any number less than 31, so the nearest whole number down is 30

8 0
2 years ago
The sugar content of the syrup is canned peaches is normally distributed. Assumethe can is designed to have standard deviation 5
andreyandreev [35.5K]

Answer: 0.50477

Step-by-step explanation:

Given : The sugar content of the syrup is canned peaches is normally distributed.

We assume the can is designed to have standard deviation \sigma=5 milligrams.

The sampling distribution of the sample variance is chi-square distribution.

Also,The data yields a sample standard deviation of s=4.8 milligrams.

Sample size : n= 10

Test statistic for chi-square :\chi^2=\dfrac{s^2(n-1)}{\sigma^2}

i.e. \chi^2=\dfrac{(4.8)^2(10-1)}{(5)^2}=8.2944

Now, P-value = P(\chi^2>8.2944)=0.50477  [By using the chi-square distribution table for p-values.]

Hence, the chance of observing the sample standard deviation greater than 4.8 milligrams = 0.50477

8 0
2 years ago
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