Answer:








Step-by-step explanation:
Given

Convert the probability to decimal

Solving (a): P(ABC)
This is calculated as:

This gives:


Solving (b): 
This is calculated as:

In probability:

So, we have:




Solving (c): 
This is calculated as:

![P(AB^cC) = P(A) * [1 - P(B)] * P(C)](https://tex.z-dn.net/?f=P%28AB%5EcC%29%20%3D%20P%28A%29%20%2A%20%5B1%20-%20P%28B%29%5D%20%2A%20P%28C%29)



Solving (d): 
This is calculated as:

![P(A^cBC) = [1-P(A)] *P(B) * P(C)](https://tex.z-dn.net/?f=P%28A%5EcBC%29%20%3D%20%5B1-P%28A%29%5D%20%2AP%28B%29%20%2A%20P%28C%29)



Solving (e): 
This is calculated as:

![P(AB^cC^c) = P(A) * [1-P(B)] * [1-P(C)]](https://tex.z-dn.net/?f=P%28AB%5EcC%5Ec%29%20%20%3D%20P%28A%29%20%2A%20%5B1-P%28B%29%5D%20%2A%20%5B1-P%28C%29%5D)
![P(AB^cC^c) = 0.48 * [1-0.48] * [1-0.48]](https://tex.z-dn.net/?f=P%28AB%5EcC%5Ec%29%20%20%3D%200.48%20%2A%20%5B1-0.48%5D%20%2A%20%5B1-0.48%5D)


Solving (f): 
This is calculated as:

![P(A^cBC^c) = [1-P(A)] * P(B) * [1-P(C)]](https://tex.z-dn.net/?f=P%28A%5EcBC%5Ec%29%20%20%20%3D%20%5B1-P%28A%29%5D%20%2A%20P%28B%29%20%2A%20%5B1-P%28C%29%5D)
![P(A^cBC^c) = [1-0.48] * 0.48 * [1-0.48]](https://tex.z-dn.net/?f=P%28A%5EcBC%5Ec%29%20%20%20%3D%20%5B1-0.48%5D%20%2A%200.48%20%2A%20%5B1-0.48%5D)


Solving (g): 
This is calculated as:

![P(A^cB^cC) = [1-P(A)] * [1-P(B)] * P(C)](https://tex.z-dn.net/?f=P%28A%5EcB%5EcC%29%20%20%3D%20%5B1-P%28A%29%5D%20%2A%20%5B1-P%28B%29%5D%20%2A%20P%28C%29)
![P(A^cB^cC) = [1-0.48] * [1-0.48] * 0.48](https://tex.z-dn.net/?f=P%28A%5EcB%5EcC%29%20%20%3D%20%5B1-0.48%5D%20%2A%20%5B1-0.48%5D%20%2A%200.48)


Solving (h): 
This is calculated as:

![P(A^cB^cC^c) = [1-P(A)] * [1-P(B)] * [1-P(C)]](https://tex.z-dn.net/?f=P%28A%5EcB%5EcC%5Ec%29%20%20%3D%20%5B1-P%28A%29%5D%20%2A%20%5B1-P%28B%29%5D%20%2A%20%5B1-P%28C%29%5D)
![P(A^cB^cC^c) = [1-0.48] * [1-0.48] * [1-0.48]](https://tex.z-dn.net/?f=P%28A%5EcB%5EcC%5Ec%29%20%20%3D%20%5B1-0.48%5D%20%2A%20%5B1-0.48%5D%20%2A%20%5B1-0.48%5D)


I'm assuming the function is f(x) = 100(0.7)^x. This is the same as y = 100(0.7)^x because y = f(x).
Plug in x = 0 to get
y = 100(0.7)^x
y = 100(0.7)^0
y = 100(1)
y = 100
So (x,y) = (0,100) is one point on this function curve
Plug in x = 2 to get
y = 100(0.7)^x
y = 100(0.7)^2
y = 100(0.49)
y = 49
So (x,y) = (2,49) is another point on this curve
In summary, the two points on this function curve are (0,100) and (2,49)
1/100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 0000000000000000000000000000 etc.
Answer:
.0025
Step-by-step explanation:
.25%/100=.0025
It's 78π inches so probably d.