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Brrunno [24]
3 years ago
5

How do you get a pmp in project management and do you need a college degree first

Computers and Technology
1 answer:
Gre4nikov [31]3 years ago
5 0

Answer:

Register to become a member of the Project Management Institute (PMI)®.

Take our PMP certification training course to satisfy the required 35 hours (PDUs) education requirement.

Submit your PMP exam application online.

Schedule your exam with Pearson VUE.

Take and Pass the PMP Exam.

If you have something less than a four-year college degree (i.e. high school diploma or associates degree), you can still get your PMP certification, but the requirements increase. Here you would have to show five years of overall project work experience, as well as 7,500 hours for the volume requirement.

Explanation:

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While using the CLI on a Windows 10 64-bit computer with a single HDD and a single volume, you want to move from the current dir
dimulka [17.4K]

Answer:

50-64

Explanation:

We know this because I said so

5 0
3 years ago
Create an instance of your queue that accepts java.lang.String Objects. Starting with an empty queue, use the enqueue(E e) metho
Aleksandr-060686 [28]

Answer:

Code is given below:

Explanation:

ode.java:

public class Node

{

String data;

Node next;

Node prev;

public Node(String data,Node next, Node prev){

this.next=next;

this.data=data;

this.prev=prev;

}

public Node(){

}

public String getData(){

return data;

}

public void setData(String data){

this.data=data;

}

public Node getNext(){

return next;

}

public void setNext(Node next){

this.next=next;

}

public Node getPrev(){

return prev;

}

public void setPrev(Node prev){

this.prev=prev;

}

}

Linked Queue.java:

public class LinkedQueues {

    Node head ;

   Node tail;

int size=0;

public Oueues(){

   this.head=null;

   this.tail=null;

}

public boolean isEmpty()

{

   return head == tail;

}    

 public int getSize()

    {

          return size;

  }    

 public void insert(String data){

   Node tmp = new Node(data,null,null);

    tmp.data=data;

    tmp.next=null;

    if(head==null){

        head=tail=tmp;

        head.prev=null;

    }

    else{

        tail.next=tmp;

        tmp.prev=tail;

        tail=tmp;

 }    

 }

 public String remove(){

  if(head.next==tail)

      return null;// list empty

  Node tmp=head.next;

  head.next=tmp.next;

  tmp.next.prev=head;

  list();

  return tmp.data;

 }

 public void list(){

     System.out.println("Queues");

     if(size==0){

         System.out.println("İs Empty");

     }

    Node tmp=head;

    while(tmp !=tail.getNext()){

        System.out.println(tmp.getVeri()+" ");

      tmp= tmp.getNext();

    }

     System.out.println();

 }

Linkedstack.java:

public class LinkedStack {

Node head = null;

Node tail = null;

int size=0;

     public int getSize() {

    return size;

      }

  public boolean isEmpty()

      {

   return head == null;

   }    

 public void Push(String data) {

    tail = head;

   head = new Node(data,null,null);

   head.data=data;

   head.next= tail;

   head.prev = null;

   if(tail != null) {

       tail.prev=head;

   }

   size++;

 }

 public void Pop() {

   if (!isEmpty()) {

       head = head.next;   // delete first node

       size--;

   } else {

       System.out.println("İs Empty");

   }

}

  public void Top() {

   Node tmp = head;

   while (tmp != null) {

       System.out.println(tmp.getData());

       tmp = tmp.getNext();

   }

}

 }

ArrayBasedQueue.java

import java.util.LinkedList;

import java.util.Queue;

 

public class ArrayBasedQueue

{

 public static void main(String[] args)

 {

   Queue<Integer> q = new LinkedList<>();

 

   // Adds elements {0, 1, 2, 3, 4} to queue

   for (int i=0; i<5; i++)

    q.add(i);

 

   // Display contents of the queue.

   System.out.println("Elements of queue-"+q);

   int removedele = q.remove();

   System.out.println("removed element-" + removedele);

 

   System.out.println(q);

   int head = q.peek();

   System.out.println("head of queue-" + head);

 

   int size = q.size();

   System.out.println("Size of queue-" + size);

 }

}

ArrayBasedStack.java:

import java.io.*;

import java.util.*;

 

public class ArrayBasedStack

{

static void stack_push(Stack<Integer> stack)

{

for(int i = 0; i < 5; i++)

{

stack.push(i);

}

}

 

// Popping element from the top of the stack

static void stack_pop(Stack<Integer> stack)

{

System.out.println("Pop :");

 

for(int i = 0; i < 5; i++)

{

Integer y = (Integer) stack.pop();

System.out.println(y);

}

}

 }

TestTimes.java:

public class TestTimes implements TestTimesInterface

{

 public static enum TimeUnits {};

 public static enum MemoryUnits{};

}

Driver.java:

public class driver

{

public static void main(String args[])

{

   Scanner s = new Scanner(System.in);

   LinkedStack y = new LinkedStack();

   LinkedQueues k = new LinkedQueues();

   ArrayBasedStack as=new ArrayBasedStack();

     ArrayBasedQueue as=new ArrayBasedQueue();

   FileWriter fwy;

   FileWriter fwk;

   File stack = new File("stack.txt");

   if (!stack.exists()) {

       stack.createNewFile();

   } else {

       System.out.println("already exists ");

   }

   BufferedReader reader = null;

   reader = new BufferedReader(new FileReader(stack));

   String line = reader.readLine();

   while (line != null) {

       y.Push(line = reader.readLine());

       System.out.println(line);

   }

   File queue = new File("queue.txt");

   if (!queue.exists()) {

       queue.createNewFile();

   } else {

       System.out.println("already exists ");

   }

   BufferedReader read = null;

   read = new BufferedReader(new FileReader(queue));

   String lines = read.readLine();

   while (lines != null) {

       lines = read.readLine();

       k.insert(lines);

       System.out.println(lines);

   }

int choice;

     System.out.println("1. Stack out- queue add");

     System.out.println("2. Stack add- queue out");

     System.out.println("3. Stack and queue ");

     System.out.println("4. File writer");

     choice = s.nextInt();

   switch (choice) {

       case 1:

           k.insert(s.next());

           k.list();

           y.pop();

           break;

       case 2:

         y.Push(s.next());

           y.Top();

         k.remove();

           break;

       case 3:

           y.Top();

           k.list();

           break;

       case 4:

           fwy = new FileWriter(stack);

           Node no = y.head;

           while (no.next != null) {

               fwy.write("\n" + no.data);

               no = no.next;

           }

           fwy.flush();

           fwy.close();

           fwk = new FileWriter(queue);

           Node noo = k.head;

           while (noo.next != null) {

               fwk.write("\n" + noo.data);

               noo = noo.next;

           }

           fwk.flush();

           fwk.close();

           break;

        }

 

}

}

6 0
3 years ago
Is technology a legal discipline or law is a technological artifact.
ANEK [815]

Answer:Technology law scholars have recently started to consider the theories of affordance and technological mediation, imported from the fields of psychology, human-computer interaction (HCI), and science and technology studies (STS). These theories have been used both as a means of explaining how the law has developed, and more recently in attempts to cast the law per se as an affordance. This exploratory paper summarises the two theories, before considering these applications from a critical perspective, noting certain deficiencies with respect to potential normative application and definitional clarity, respectively. It then posits that in applying them in the legal context we should seek to retain the relational user-artefact structure around which they were originally conceived, with the law cast as the user of the artefact, from which it seeks certain features or outcomes. This approach is effective for three reasons. Firstly, it acknowledges the power imbalance between law and architecture, where the former is manifestly subject to the decisions, made by designers, which mediate and transform the substance of the legal norms they instantiate in technological artefacts. Secondly, from an analytical perspective, it can help avoid some of the conceptual and definitional problems evident in the nascent legal literature on affordance. Lastly, approaching designers on their own terms can foster better critical evaluation of their activities during the design process, potentially leading to more effective ‘compliance by design’ where the course of the law’s mediation by technological artefacts can be better anticipated and guided by legislators, regulators, and legal practitioners.

Keywords

Affordance, technological mediation, postphenomenology, legal theory, compliance by design, legal design

7 0
3 years ago
Many contemporary languages allow two kinds of comments: one in which delimiters are used on both ends (multiple-line comments),
m_a_m_a [10]

Answer and Explanation:

Multiple-line comments :

Advantage :In the event that we need to remark out of zone of the given program , we can utilize it.

Disadvantage : In numerous line results are in reduced unwavering quality. It stretches out the remark as far as possible of the following comment.For least difficult approach to unintentionally leave off the last delimiter, which successfully expelling code from the program.

Single Line Comments :

Advantage :In the event that you need to close all the delimiter before close the program we utilize this kind of remarks.

Disadvantage : It put more burden on your program .It repeated on every line of a block of comments

3 0
2 years ago
Which animation principle is applied to ‘sell’ the beginning of the character jump?
Sunny_sXe [5.5K]
Anticipation I think so but I’m not sure:)
3 0
2 years ago
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