For this question the answer is the second one
Answer:

Step-by-step explanation:
Here is the full question
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times. We'll assume we can make "perfect folds," where each fold makes the folded paper exactly twice as thick as before - and we can make as many folds as we want.
Write a function g that determines the thickness of the folded paper (in mm) in terms of the number folds made, n. (Notice that g(0) 0.05,)

The function g has an inverse. The function g⁻¹ determines the number of folds needed to give the folded paper a thickness of t mm. Write a function formula for g⁻¹).
<u>SOLUTION:</u>
If we represent g(n) with t;
Then

Taking logarithm of both sides; we have :

Fifty six million eight hundred ninety three thousand
The diagram can be redrawn as,
The value of x and y can be determined as,
![\begin{gathered} \tan C=\frac{AB}{BC} \\ \tan 45^{\circ}=\frac{x}{7\sqrt[]{2}} \\ x=7\sqrt[]{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctan%20C%3D%5Cfrac%7BAB%7D%7BBC%7D%20%5C%5C%20%5Ctan%2045%5E%7B%5Ccirc%7D%3D%5Cfrac%7Bx%7D%7B7%5Csqrt%5B%5D%7B2%7D%7D%20%5C%5C%20x%3D7%5Csqrt%5B%5D%7B2%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} \cos C=\frac{BC}{AC} \\ \cos 45^{\circ}=\frac{7\sqrt[]{2}}{y} \\ y=14 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%20C%3D%5Cfrac%7BBC%7D%7BAC%7D%20%5C%5C%20%5Ccos%2045%5E%7B%5Ccirc%7D%3D%5Cfrac%7B7%5Csqrt%5B%5D%7B2%7D%7D%7By%7D%20%5C%5C%20y%3D14%20%5Cend%7Bgathered%7D)
Thus, option (D) is the correct solution.
<span>A. 30 ft
The formula for the area of a rectangle is width x length = area. Knowing this formula, we can solve for the length by dividing the area by the width. 600 divided by 20 is 30.</span>