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Komok [63]
3 years ago
5

(16x)^1/2 x (25^3/2)

Mathematics
1 answer:
zimovet [89]3 years ago
7 0
Solve for x:
31250 x^(3/2) = 0
Divide both sides by 31250:
x^(3/2) = 0
Raise both sides to the power of 2/3:
Answer:  x = 0
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Solve for y in terms of x
Alika [10]

Answer:

(a) 3 - 2x - 2x²  (b) -21

Step-by-step explanation:

given, y +2x² = 3 -2x

make y the subject:

y = 3 - 2x - 2x²

if y = f(x)

then

f(x) = 3 - 2x - 2x²

(b)<u> to find f(3) we need to replace x with 3:</u>

<u />

3 - 2(3) - 2*(3)²

-21

3 0
2 years ago
Please help and explain your work
Ilia_Sergeevich [38]

Answer:

416mm³

Step-by-step explanation:

Volume of rectangular prism

= 10.4mm × 5mm × 8mm

= 416mm³

6 0
2 years ago
Susannah has a high-yield savings account into which she deposits $140 each month. At the beginning of the year, Susannah's acco
motikmotik

Answer:

Her account balance will be $2,080 at the end of the year

Step-by-step explanation:

Let

y ----> Susannah's account balance

x ---> is the  amount of time in months

we have

y=140x+400

This is a linear equation in slope intercept form

where

The slope or unit rate is equal to

m=\$140\ per\ month

The y-intercept or initial value is equal to

b=\$400

Remember that

One year is equal to 12 months

so

For x=12 months

substitute in the linear equation

y=140(12)+400=\$2,080

5 0
3 years ago
The sales tax on a used car is $144, and the sales tax rate is 5%. Find the purchase price (the price before tax are added).
kupik [55]

Answer:

151.20

Step-by-step explanation:

3 0
2 years ago
The absolute value function is written f(x) = |x|. It is composed of the lines y = x and y = -x. Its domain is the real numbers
Katena32 [7]
1.
no, there will never be a negative y-value.  <span>y= |x| will always be nonnegative. |x| can be distance x is from 0 and a distance can never be negative.

</span>2.
you can define it as
y = |x| = x if x ≥ 0, -x if x < 0

absolute value can be interpreted as a function that does not allow negative real numbers, forcing them to be positive (leaving 0 alone). if the input x is more than or equal 0, then x stays positive so there is no need to do anything: "x if x ≥ 0".
if the input is less than 0, then it is an negative number and needs a negative coefficient to negate the negative: "-x if x < 0"

example: if x = -3, then it will take the "-x if x < 0" piece resulting in y = -(-3) = 3, which is what |-3| does

if x = 1, it will take the "x if x ≥ 0" piece and just have y = 1 which is what |1| does.

for x = 0, it will take the "x if x ≥ 0" and just have y = 0 which is what |0| does
4 0
2 years ago
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