Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
The first step for solving this question is put both of your given expressions into one and then subtract them. This will look like the following:
8 ×
- 2 × 10²]
Now to make the calculation easier,, factor the expression.
(8 ×
- 2) × 10²
Evaluate the power inside the parenthesis.
(8 × 10000 - 2) × 10²
Evaluate the power outside the parenthesis.
(8 × 10000 - 2) × 100
Multiply the numbers inside the parenthesis.
(80000 - 2) × 100
Subtract the numbers in the parenthesis.
79998 × 100
Lastly,, multiply the numbers together to get your final answer.
7999800
This means that 8 ×
is 7999800 times larger than 2 × 10².
Let me know if you have any further questions.
:)
Answer:
B
Step-by-step explanation:
9 multiple 2m = 18m
9 multiple 5n = 45n
9 multiple 10= 90
For any equation,
assume solution of a form, 
Which leads to,
Simplify to,
Then find solutions,
For non repeated real root y, we have a form of,
Following up,
For two non repeated complex roots 
where,
and,
the general solution has a form of,
Or in this case,
Now we just refine and get,
Hope this helps.
r3t40
Answer: 8 buses
Step-by-step explanation:
You need 8 buses minimum
