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nadezda [96]
2 years ago
11

%5E%7B2%7D%20" id="TexFormula1" title=" { \alpha }^{2} \beta + \alpha { \beta }^{2} " alt=" { \alpha }^{2} \beta + \alpha { \beta }^{2} " align="absmiddle" class="latex-formula">
Please solve this ​
Mathematics
1 answer:
sineoko [7]2 years ago
4 0
If a and B are the zoros of the quadratic polynomial p(x)=4x^2 - 5x-1, find value of a^2B + aB^2 .

Solution

SINCE a and B are the roots of the polynomial: 4x^2-5x-1

Sum of the roots a+B =5/4

Product of the roots aB=-1/4

HENCE

a^2B+aB^2=aB(a+B)=5/4(-1/4)=-5/16

Concept:Relationship Between Zeroes and coefficients of a Polynomial
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Find slope of -2,3 and 4,-5
bulgar [2K]
-2,3 is (x1,y1) and (4,-5) is (x2,y2) so you do y2-y1/x2-x1

y2-y1 is -5-3 which is -8 and x2-x1 is 4-(-2) which is 6 so you get

-8/6= -4/3
4 0
2 years ago
Plz tell me someone know how to do this!!<br> I'll mark brainliest
anygoal [31]

Answer:

It would be the second option

Step-by-step explanation:

z:28 is the ratio of the shorter triangle's side to the larger triangle's side, so is 27:45.

5 0
3 years ago
What is the answers?
34kurt
Cos theta would be (adjacent side) / (hypotenuse), or 8/29.  

Thus, the angle theta would be the inverse cosine of 8/29, which is 

1.291 radians or 73.987 degrees.

Given this result, just take the sine of this angle.
6 0
3 years ago
5t^2 - 5.5 - 3.5t + 1.5t^2 +4t
RideAnS [48]
The answer is 6.5t2+0.5t−5.5 , it’s simplified
8 0
3 years ago
Read 2 more answers
Brainliest, what is the total measure of angles 8 and 5 of angle 7 equals 61
guapka [62]
Lines equal 180°. The line with angles 5 and 7 equals 180°. If angle 7 equals 61°, then angle 5 equals 119° (180° - 61°= 119°).

Angles 5 and 8 are opposite vertical angles, which are always congruent (equal), so angles 5 and 8 both equal 119°.

119° (angle 5) + 119° (angle 8)= 238°


ANSWER: The two angles total 238° (bottom choice).

Hope this helps! :)
7 0
3 years ago
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