%5E%7B2%7D%20" id="TexFormula1" title=" { \alpha }^{2} \beta + \alpha { \beta }^{2} " alt=" { \alpha }^{2} \beta + \alpha { \beta }^{2} " align="absmiddle" class="latex-formula">
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1 answer:
If a and B are the zoros of the quadratic polynomial p(x)=4x^2 - 5x-1, find value of a^2B + aB^2 .
Solution
SINCE a and B are the roots of the polynomial: 4x^2-5x-1
Sum of the roots a+B =5/4
Product of the roots aB=-1/4
HENCE
a^2B+aB^2=aB(a+B)=5/4(-1/4)=-5/16
Concept:Relationship Between Zeroes and coefficients of a Polynomial
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Answer:
Step-by-step explanation:
If you want a solution:
<em>subtract 5 from both sides</em>
<em>multiply both sides by 3</em>
Y= mx+b
Since this line is horizontal it's slope = 0 ==> the y=b
It passes by the point (3,-3) that means b=-3 & the equation is y=-3
Answer:
1. subtracting 5
2. adding 20
3. dividing by 1/2
4. multiplying by 10
Answer:
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I’m not sure if the 15 is the question number but if it is the answer is 32. use PEMDAS
