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VMariaS [17]
3 years ago
6

A landscaper makes a $2,000 profit in a week when he services 25 lawns. He makes a $600 profit in a week when he services 11 law

ns. If his profit for the week is a linear function of the number of lawns serviced, how much profit would he recieve in a week that he services 36 lawns?
Mathematics
1 answer:
SOVA2 [1]3 years ago
8 0
2000 - 600 = 1400
-------------- 
25 - 11 = 14

100 dollars per 1 lawn. 

36 * 100 = 3,600 

He will earn $3,600.
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Please help explanation if possible
expeople1 [14]

9514 1404 393

Answer:

  • steeper
  • up (4 units)

Step-by-step explanation:

When the equation of the line is in the form ...

  y = mx + b

the coefficient 'm' is the slope of the line, and the value 'b' is the y-intercept, the point on the y-axis where the line crosses.

We say the line is "steeper" when the magnitude of the slope is greater. Line B, with its slope of 7 will be steeper than line A, with its slope of 3.

  the new slope is steeper

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The y-intercept of line A is -3. The y-intercept of line B is +1, so it crosses the y-axis above the point where line A crosses. One could say that line B is shifted up, when referring to the y-intercept.

3 0
3 years ago
In his will, Mr. Banks left 50% of the value of his property to his
Rashid [163]

The value of Mr Banks's property was $250,000

What percentage of the property is left for charity?

The percentage of property left for charity can be determined as the 100% of the property minus all percentages given to others

% left for charity=100%-50%-22%-16%

% left for charity=12.00%

12.00% of the property=$30,000

1.00% of the property =$30,000/12

1.00% of the property =$2,500

100.00% of the property=$2500*100

100.00% of the property=$250,000

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6 0
2 years ago
Which ones are the distance formula and midpoint formula?
lutik1710 [3]

Answer:

The distance formula is d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)2}

The midpoint formula is \left(\frac{x_1\:+x_2}{2}\right),\left(\frac{y_1-y_2}{2}\right)

Step-by-step explanation:

apply the pythagorean theorem on a coordinate grid

7 0
3 years ago
Highest/greatest common factor of 50 and 125
Nata [24]
50 =2×5×5 125=5×5×5 Hoghest common factor = 5×5 =25
5 0
3 years ago
Read 2 more answers
suppose a farmer encloses a rectangular region of a land next to a river. fencing will be used on 3 sieds, and none is needed al
nexus9112 [7]

Answer:

Dimensions :

x (the longer side, only one side with fence )   =  90  ft

y ( the shorter side two sides with fence )        =  45  ft

Total fence used   45 * 2  +  90    =  180 ft

A(max)  =  

Step-by-step explanation: If a farmer has 180 ft of fencing to encloses a rectangular area with fence in three sides and the river on one side, the farmer surely wants to have a maximum enclosed area.

Lets call "x" one the longer side  ( only one of the longer side of the rectangle will have fence, the other will be along the river and won´t need fence. "y" will be the shorter side

Then we have:

P = perimeter  =  180  =  2y  +  x        ⇒   y  =  ( 180 - x )  / 2        (1)

And   A (r)   =  x * y

A(x)   =  x  *  ( 180 - x ) /2       ⇒   A(x)   = (180/2) *x   -  x² / 2

Taking derivatives on both sides of the equation :

A´(x)   =  90   -  x    

Then if    A´(x)   =  0   ⇒        90   -  x    =  0     ⇒   x  =  90 ft

and from :       y  =  ( 180 - x )  / 2     ⇒     y  =  90/2

y  =  45  ft

And

A(max)  =  90 * 45    =  4050  ft²

4 0
3 years ago
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