32. 16 through opposite vertices and 16 through the centres of opposite sides
Considering that the addresses of memory locations are specified in hexadecimal.
a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations
b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095
<u>applying the given data </u>:
a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )
( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )
= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )
= 61440 + 3840 + 240 + 15 = 65535
∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations
b) The range of hex addresses with a memory location of 4096
= 0000₁₆ to FFFF₁₆ = 0 to 4096
∴ the range = 4095
Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.
Learn more : brainly.com/question/18993173
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Solution:
Put all the answer choices into expanded form.
3^9 = 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3
1^8 = 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1
9^3 = 9 x 9 x 9
8^1 = 8
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Answer:
We can see that the only way to write to write 9 x 9 x 9 in exponential form is c) 9^3
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Hope This Helped! Good Luck!
Answer:
1.25 g
Step-by-step explanation:
you start with 20g at 0 seconds.
divide by half after 2 seconds and you have 10g.
at 4 seconds you have 5g.
at 6 seconds you have 2.5g.
at 8 seconds you have 1.25g.
D = m/v
V = 2•2•2 = 8cm^3
D = 12/8 = 1.5g/cm^3
Answer is B
