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almond37 [142]
3 years ago
10

Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The

speed of one of the planes was 200 km/hour slower than the speed of the other plane, and so it arrived at its destination 1.5 hours after the faster plane. Find the speeds of both planes.
Mathematics
2 answers:
Wewaii [24]3 years ago
3 0

answer:133.3km

Step-by-step explanation:

hammer [34]3 years ago
3 0

Answer:

Can I have the brainliest answer I’m new

Step-by-step explanation:

i love you ♥️♥️

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What is the distance between the points (-3,5) and (-3,-9) ? ​
Natasha2012 [34]

Answer:

14

Step-by-step explanation:

The distance between two points is given by

d = sqrt( (y2-y1) ^2 + (x2-x1)^2)

   = sqrt((-9-5)^2 + (-3- -3)^2)

    = sqrt(( -14)^2 +(-3+3)^2)

   = sqrt((-14)^2 +0)

  = sqrt((14)^2)

  = 14

5 0
4 years ago
The scheduled arrival time for a daily flight from Boston to New York is 9:30 am. Historical data show that the arrival time fol
mamaluj [8]

Answer:

a) E(A)=\frac{0+50}{2}=25 min

Sd(A) =\sqrt{208.3333 min^2}=14.43 min

b) P(A>25) = 1-P(A\leq 25)=1-\frac{25-0}{50-0}= 1-0.5 = 0.5

Step-by-step explanation:

Part a

Let A the random variable that represent "The arrival time (minutes) for a daily flight from Boston to New York ". And we know that the distribution of A is given by:

A\sim Uniform(a=0 ,b=50)

We select our starting point a=0 representing 9:05 AM and the amount of minutes between 9:05 am to 9:55 am are 50 ans for this reason b =50

For ths uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

E(A)=\frac{0+50}{2}=25 min

And the variance is given by:

Var(A)= \frac{(b-a)^2}{12}=\frac{(50-0)^2}{12}=208.3333 min^2

And the standard deviation by definition is just the square root of the variance:

Sd(A) =\sqrt{208.3333 min^2}=14.43 min

Part b

If we convert 9:30 AM to our scale we know that we have 25 minutes between 9:05 AM and 9:30 AM.

For this case we want to find this probability: P(A>25)

And we can find this probability using the complement rule like this:

P(A>25) = 1-P(A\leq 25)

And we can use the cumulative distribution function given by:

F(A) = \frac{A-a}{b-a}

And we got:

P(A>25) = 1-P(A\leq 25)=1-\frac{25-0}{50-0}= 1-0.5 = 0.5

5 0
3 years ago
Round to the place of
larisa86 [58]

Answer:

24,600

Step-by-step explanation:

5 and more you round it up

4 or less you let rest

3 0
3 years ago
Maureen has two hollow containers. One is a 5 cm cube and the other is a cylinder of radius 2 cm. She completely fills the cube
rosijanka [135]

Answer:

it's 9.947

Step-by-step explanation:

for this we need an equation which contain height in it so we used volume in both so we get height

π2^2h=5*5*5

π4h=125

h=9.947

7 0
3 years ago
Clayton needs to reflect the triangle below across the line y = x. On a coordinate plane, triangle A B C has points (5.5, 7), (6
Ksju [112]

Answer:

Clayton could use the relationship (x,y) - (y,x) to find the points of the image.

C’ will remain in the same location as C because it is on the line of reflection.

The image and the pre-image will be congruent triangles.

The image and pre-image will not have the same orientation because reflections flip figures

Step-by-step explanation:

Clayton needs to reflect the triangle below across the line y=x

Which statements about the reflection are true? Check all that apply.

Clayton could use the relationship (x,y) - (y,x) to find the points of the image.Clayton could negate both the x and y values in the points to find the points of the image.C’ will remain in the same location as C because it is on the line of reflection.C’ will move because all points move in a reflection.The image and the pre-image will be congruent triangles.The image and pre-image will not have the same orientation because reflections flip figures.

Solution:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

Reflection is the flipping of a figure over a line. If a point A(x, y) is reflected over the line y=x, the new location is A'(y, x).

If the triangle ABC with vertices A(5.5, 7), B(6, 2), C(4, 4) is reflected over the line y=x, the new location would be A'(7, 5.5), B'(2, 6) and C'(4, 4).

A. Clayton could use the relationship (x,y) - (y,x) to find the points of the image. Reflection across the line y = x is the swapping of the x and y coordinates. Option A is correct

B. Clayton could negate both the x and y values in the points to find the points of the image. Option B is wrong

C. C’ will remain in the same location as C because it is on the line of reflection. C is on the line of reflection, hence it remains the same. Option C is correct.

D. C’ will move because all points move in a reflection.

Option D is wrong.

E. The image and the pre-image will be congruent triangles.

Option E is correct. Reflection preserves the shape and length of an object.

F. The image and pre-image will not have the same orientation because reflections flip figures. Option F is correct

8 0
3 years ago
Read 2 more answers
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