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dmitriy555 [2]
3 years ago
6

CAN SOMEONE PLEASE HELP MEEEE? PLEASSEEE. EMERGENCY!! 30 POINTS!! PLEASE AND THANK YOU.

Mathematics
2 answers:
Alexus [3.1K]3 years ago
6 0
I can confirm that the person above is correct
ladessa [460]3 years ago
3 0

Answer:

\sqrt{2n^{2}}

You have the side lengths of the two legs, n and n.

Then, using the pythagorean theorem you have to find the length of the third side:

a^2 + b^2 = c^2\\n^2 + n^2 = c^2\\2n^2 = c ^ 2\\\sqrt{2n^2} = c

where c is the third side

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Which of the following is the equation of a circle with a radius of 10 cm and center at (–3, 6)?
Volgvan

The equation of the circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have:

r=10\\(-3,\ 6)\to h=-3,\ k=6

Substitute:

(x-(-3))^2+(y-6)^2=10^2\\\\(x+3)^2+(y-6)^2=100

4 0
3 years ago
Perimeter of a triangle is 27cm,if two sides measure 9cm and 7.8cm,find the measure of third side?
fredd [130]

Answer:

10.2cm

Step-by-step explanation:

Perimeter is the sum of the lengths of all sides.

1st side: 9cm

2nd side: 7.8cm

Perimeter: 27cm

Perimeter = 1st + 2nd +3rd side of a triangle

27cm = 9cm +7.8cm + 3rd side

3rd side = 27cm - 9cm -7.8cm

              = 10.2cm

8 0
2 years ago
Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
3 years ago
Read 2 more answers
Find the difference. 748.20 - 18.044 *
konstantin123 [22]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

Let's see...

Step-by-step explanation:

748.20 - 18.044

<h3>= 730.156 </h3>

I hope this helps!

- sincerelynini

4 0
3 years ago
Read 2 more answers
FAST HURRY HELP PLZZ
Angelina_Jolie [31]

Answer:

I think its A but not 100 percent sure

Step-by-step explanation:

3 0
2 years ago
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