CAN SOMEONE PLEASE HELP MEEEE? PLEASSEEE. EMERGENCY!! 30 POINTS!! PLEASE AND THANK YOU.

Mathematics

2 answers:

Alexus [3.1K]3 years ago

6 0

I can confirm that the person above is correct

ladessa [460]3 years ago

3 0

Answer:

$\sqrt{2n^{2}}$

You have the side lengths of the two legs, n and n.

Then, using the pythagorean theorem you have to find the length of the third side:

$a^2 + b^2 = c^2\\n^2 + n^2 = c^2\\2n^2 = c ^ 2\\\sqrt{2n^2} = c$

where c is the third side

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Please help me

Sedbober [7]

The answer is 0.2
Hope this helps

4 0

3 years ago

Read 2 more answers

How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove

BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

$\dfrac{9}{n^2+1} =\dfrac{n+3}{4}$

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

$\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\$