The set A satisfying the given inequality is A = (-
, -10].
<h3>What are some properties of an inequality relation? </h3>
Following are some facts which are true for an inequality relation:
- Equal numbers can be added or subtracted from both sides of an inequality without affecting the inequality sign.
- The Inequality sign is unchanged if both sides are multiplied or divided by a positive number, but when multiplied or divided by a negative number the inequality sign is reversed.

Since y ∈ B, -2 ≤ y ≤ 7. So,

The set {-x | inequality (1) holds ∀ y ∈ B} is [10,
) i.e.
10 ≤ -x ≤
.
Multiplying -1 throughout gives
-10 ≥ x ≥ -
.
x, thus, lies in the range A = (-
, -10}.
Learn more about the inequality here.
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<h3>Question </h3>
Find the set A such that for x ∈ A

∀y ∈ B = {y ∈ R | -2 ≤ y ≤ 7}.
#SPJ4
1.) 6.50(m)= x
2.) x= 6.00m + 50
3.)6.50m-0= x
Answer:
A
Step-by-step explanation:
Use Pythagorean Theorem, which is for side lengths of right triangles.
a^2 + b^2 = c^2 (c is the hypotenuse)
Common combination is 3-4-5. Just by looking at the answers, I can see A is 3-4-5 except everything is multiplied by 2.
B is wrong. It would be 5-12-13 if it were a RT.
C is wrong. 3-4-5
D is wrong. 4 + 25 = 49 is not an equation.
Answer:
Just plug In values for x and find the output.
Step-by-step explanation:
If x is 1 then y is -1/3(1)+4, which is 11/3. (1, 11/3)
If x is 2 then y is -1/3(2)+4, which is 10/3. (2,10/3)
And so on...