Answer: x= 207.8873386
Step-by-step explanation:
expecting both 2x-15 and 3x are angles in radiant, let's draw a rhombus ABCD
∠ABC = 2x-15
∠ BCD = 3x
∠ABC + < BCD= π ( 180° in radiant)
2x - 15 + 3x = π
5x - 15 = π
x - 3 = 1/5π
= 3.628318531 = 207.8873386
2x−15°+3x=180
5x-15°=180
5x=195°
x=39°
Answer:4
Step-by-step explanation:
Are a and b two points on a line
If they are you can use the distance formula
Answer:
40
Step-by-step explanation:
(2x+1/(2x))^5 *(2x -1/(2x))^5
= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2
= (4x^2-1/4(x)^2)^5
now
x =4x^2. ,a = 1/4(x)^2 ,n =5
we have
general term = Cr *x^r *a^(n-r)
= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)
= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)
= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)
= Cr * 4(2r-n) *x(4r-2n)
now for x^2
4r-2n = 2
4r -10=2
4r =12
r = 3
now for coeff
C(5,3) * 4^(2*3-5)
5!/(3!*(5-3)!) * 4
5*4/(2*1)*4
40
