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3 years ago

Can someone solve this?

Mathematics

1 answer:

Vlada [557]3 years ago

5 0

Answer:

1) B and C

2) 0 < 5x - 10 < 50

10 < 5x < 60

2 < x < 12

3) B

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3.5

Step-by-step explanation:

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2 years ago

The endpoints of ab are a(1,4) and b(6,-1). If point c divides ab in the ratio 2:3, the coordinates of c are ?. If point d divid

Pachacha [2.7K]

Answer:

The coordinate C:(3,2) and coordinate $D:\left ( \dfrac{11}{5},\dfrac{14}{5}, \right )$

Step-by-step explanation:

1. The endpoints of AB are A(1,4) and B(6,-1)

If point C divide AB in the ratio 2:3

Formula:

$\text{Section formula}(x,y)=\left ( \dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}, \right )$

Where,

$(x_1,y_1)\rightarrow A(1,4)$

$(x_2,y_2)\rightarrow B(6,-1)$

$m:n\rightarrow 2:3$

$C:(x,y)$

$C:\left ( \dfrac{2\cdot 6+3\cdot 1}{2+3},\dfrac{2\cdot -1+3\cdot 4}{2+3}, \right )$

$C:\left ( \dfrac{12+3}{5},\dfrac{-2+12}{5}, \right )$

$C:(3,2)$

2. The endpoints of AC are A(1,4) and B(3,2)

If point D divide AC in the ratio 3:2

$(x_1,y_1)\rightarrow A(1,4)$

$(x_2,y_2)\rightarrow C(3,2)$

$m:n\rightarrow 3:2$

$D:(x,y)$

$D:\left ( \dfrac{3\cdot 3+2\cdot 1}{2+3},\dfrac{3\cdot -1+2\cdot 4}{2+3}, \right )$

$D:\left ( \dfrac{9+2}{5},\dfrac{6+8}{5}, \right )$

$D:\left ( \dfrac{11}{5},\dfrac{14}{5}, \right )$

Hence, The coordinate C:(3,2) and coordinate D: $\left ( \dfrac{11}{5},\dfrac{14}{5}, \right )$

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