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2 years ago

PLEASE HELP! ASAP! I WILL GIVE BRAINLIEST What is 365x853. Can you help me? Thank you!

Mathematics

2 answers:

Dafna11 [192]2 years ago

8 0

311,345 is the answer

Pavel [41]2 years ago

4 0

311,345

Hope this helps!

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Find the sine of R. <br> A)12/13<br> B)13/12<br> C)5/12<br> D)5/13

enot [183]

Answer:

5/13

Step-by-step explanation:

sin R = opp side/ hypotenuse

sin R = 5/13

5 0

3 years ago

Ben earns a salary of $120 a week plus $25 for each table he sells at

gtnhenbr [62]

Answer:

add 25 each time and count how many times you add it on

Step-by-step explanation:

and that will be your answer

7 0

2 years ago

Which of the following functions are homomorphisms?

Vikentia [17]

Part A:

Given $f:Z \rightarrow Z,$ defined by $f(x)=-x$

$f(x+y)=-(x+y)=-x-y \\ \\ f(x)+f(y)=-x+(-y)=-x-y$

but

$f(xy)=-xy \\ \\ f(x)\cdot f(y)=-x\cdot-y=xy$

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.

Part B:

Given $f:Z_2 \rightarrow Z_2,$ defined by $f(x)=-x$

Note that in $Z_2$ , -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular $f(x)=x$

$f(x+y)=x+y \\ \\ f(x)+f(y)=x+y$

and

$f(xy)=xy \\ \\ f(x)\cdot f(y)=xy$

Therefore, the function is a homomorphism.

Part C:

Given $g:Q\rightarrow Q$ , defined by $g(x)= \frac{1}{x^2+1}$

$g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1} \\ \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1}$

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.

Part D:

Given $h:R\rightarrow M(R)$ , defined by $h(a)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)$

$h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\ \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)$

but

$h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\ \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)$

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.

Part E:

Given $f:Z_{12}\rightarrow Z_4$ , defined by $\left([x_{12}]\right)=[x_4]$ , where $[u_n]$ denotes the lass of the integer $u$ in $Z_n$ .

Then, for any $[a_{12}],[b_{12}]\in Z_{12}$ , we have

$f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\ \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)$

and

$f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)$

Therefore, the function is a homomorphism.

7 0

3 years ago

In a survey, 56 percent of people surveyed stated truthfully that they were married, while 30 percent of the people surveyed who

lilavasa [31]

Answer:

15 surveyed

Step-by-step explanation:

8 0

3 years ago

Cada caja contiene el mismo número de cuadernos. Si Mario transporta 120 cuadernos en total en una carretilla, ¿cuántos cuaderno

DIA [1.3K]

Answer:

Se almacena un cuaderno por caja, significando 120 cuadernos en 120 cajas iguales.

Step-by-step explanation:

A partir del enunciado, podemos calcular el número de cuadernos por caja al dividir el total de cuadernos en la carretilla por el número de cajas disponibles.

$x = \frac{120\,cuadernos}{120\,cajas}$

$x = 1\,\frac{cuadernos}{caja}$

Se almacena un cuaderno por caja, significando 120 cuadernos en 120 cajas iguales.

3 0

3 years ago