What is the center of the circle represented by this equation? x2 + (y + 9)2 = 25

1 answer:

4 0

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
x^2+(y+9)^2=25\implies [x-\stackrel{h}{0}]^2+[y-\stackrel{k}{(-9)}]^2=\stackrel{r}{5^2}\qquad \qquad \quad \stackrel{center}{(0,-9)}$

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Brums [2.3K]

Answer:

7.2

Step-by-step explanation:

To reach point D from point C, you need to add 4 to the x-value of point C and take away 6 from the y-value. These numbers are the sides of the hypothetical triangle.

The Pythagorean Theorem states that $a^2+b^2=c^2$ . If we plug the side lengths in for a and b, we get $4^2 + 6^2 = c^2$ . This can be simplified to $16+36=c^2$ , or $52 = c^2$ . If we root both sides, we find that c is equal to $\sqrt{52}$ , which is slightly more than 7, at around 7.2.