Let us assume the number of CDs Kate had = x
Number of CDs given to Sue = 5x/6
Number of CDs given to Joan = (5x/6) * ( 7/8)
= 35x/48
Number of CDs given to Ann = (35x/48) * (3/5)
= 7x/16
Total number of CDs Ann received = 70
Then
7x/16 = 70
x = 160
From the above deduction, it can be concluded that the number of CDs that Kate originally had was 160. I hope that this is the answer that has actually come to your help.
I’m my opinion I thick it could be A
Answer:
I believe it is twenty-one is 7 times the size of 3
Step-by-step explanation:
Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.



Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.