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inn [45]
3 years ago
7

Find the period.

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

Answer:

The Time period of the Amount is 5 years 3 days .

Step-by-step explanation:

Given as :

The principal = p = Rs 9300

The annual rate of interest = r = 13%

The Total amount after t years = A = Rs 17,763

Let The time period = t years

<u>From Compound Interest method </u>

Amount = principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, Rs 17,763 = Rs 9300 × (1+\dfrac{\textrm 13}{100})^{\textrm t}

Or, \dfrac{17763}{9300} = (1.13)^{t}

or, 1.91 = (1.13)^{t}

Taking Log both side

Log_{10}1.91 = Log_{10}(  (1.13)^{t} )

or, 0.2810 = t × Log_{10}1.13

or, 0.2810 = t × 0.0530

∴ t - \dfrac{0.2810}{0.0530}

I.e t = 5.30 years

So, The time period = t = 5 years 3 days

Hence The Time period of the Amount is 5 years 3 days . Answer

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16th term in the geometric sequence 1024, -512, 256, ....
tresset_1 [31]

Answer:-1/32

Step-by-step explanation:

First term=a=1024

Common ratio=r=-512/1024

r=-1/2

Using them formula

Tn=a x r^(n-1)

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T16=1024 x (-1/2)^15

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T16=-1/32

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Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

  1. f : X \rightarrow Y is surjective implies there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y.
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Let us start by the first implication.

Our hypothesis is that the function f : X \rightarrow Y is surjective. From this we know that for every y\in Y there exist, at least, one x\in X such that y=f(x).

Now, define the sets X_y = \{x\in X: y=f(x)\}. Notice that the set X_y is the pre-image of the element y. Also, from the fact that f is a function we deduce that X_{y_1}\cap X_{y_2}=\emptyset, and because  f the sets X_y are no empty.

From each set X_y  choose only one element x_y, and notice that f(x_y)=y.

So, we can define the function h:Y\rightarrow X as h(y)=x_y. It is no difficult to conclude that f\circ h(y) = f(x_y)=y. With this we have that f\circ h=1_Y, and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function  h:Y\rightarrow X  such that f\circ h=1_Y.

Take an element y\in Y, then f\circ h(y)=y. Now, write x=h(y) and notice that x\in X. Also, with this we have that f(x)=y.

So, for every element y\in Y we have found that an element x\in X (recall that x=h(y)) such that y=f(x), which is equivalent to the fact that f is surjective. Therefore, the prove is complete.

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