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Elan Coil [88]
3 years ago
15

I'm having trouble with this

Mathematics
1 answer:
tester [92]3 years ago
4 0
The answer is 9

mark brainliest

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Question 5 <br> show the work please
Pani-rosa [81]

Answer:

D) 27

Step-by-step explanation:

It's a rectangle so the opposite sides are congruent to each other.

<em />

<em>Long Side:</em>

6x + 6 = 42

subtract 6 from both sides:

6x = 36

divide both sides by 6:

x = 6

<em />

<em>Short Side:</em>

5y + 5 = 30

subtract 5 from both sides:

5y = 25

divide both sides by 5:

y = 5

<em />

<em>The Equation:</em>

2x + 3y

substitute in the values:

2(6) + 3(5)

do the multiplication:

12 + 15

add the values together:

27

6 0
3 years ago
Read 2 more answers
Please do this faster than a sonic the hedghog
Sloan [31]

Answer:

-2 correct me if im wrong

5 0
3 years ago
If s and t are integers greater than 1 and each is a factor of the integer n, which of the following must be a factor of n st ?
yulyashka [42]

Answer:

A) None

Step-by-step explanation:

1) s^t shoudnt neccesarily be a factor of nst, for example, if s = 3, t = 4, and n = 12, then both s and t are factors of n, but 3^4 = 81 is not a factor of nst = 144.

2) (st)^2 shoudnt neccesarily be a factor of nst. Let s be 4, let t be 6, and let n be 12. Then n is a factor of both s and t, but (st)^2 = 24^2 is not a factor of nst = 12*24. In fact, it is a greater number.

3) Again, s+t isnt necessarily a factor of nst, let s be 2 and t be 3. Then both s and t are factor of n = 12. However 5 = s+t is not a factor of nst = 72.

So, neither of the three options is guaranteed to be a factor of nst. In fact, for s = 4, t = 6, and n = 12, none of the three options are valid.

4 0
3 years ago
Lemma 2.3.2 (Multiplication is commutative). Let n,m be natural питbers. hen n x m = mхп.
Paraphin [41]

Answer:

Multiplication is commutative.          

Step-by-step explanation:

Let n,m be two natural numbers.

We have to show that n\times m=m\times n

We will prove this by induction

For n = 1, we have n\times 1 = 1\times n = n, which is true.

Let the given statement be true for n-1 natural numbers, that is,

(n-1)\times m = m\times (n-1)

Now, we have to show that it is true for n natural numbers.

nm = (n-1)m + m = m(n-1) + m

which is equal to

(m-1)(n-1) + (n-1) + m

= (m-1)(n-1) + (m-1) + n

= n(m-1) + n

= (m-1)n + n

= mn

Hence, by principal of mathematical induction, the given statement is true for all natural numbers.

6 0
3 years ago
20 POINTS!! (will get brainliest)
storchak [24]

Answer:

46. 135°

47. 225°

47. 270°

48. 3/8

49. 3/4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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