Considering that the grows at a constant rate we can form an equation where x = how many years after it was planted
and y = its height
Now we just need to find how many feet it grows each year. To do that we just need to compare its height from a certain age to another:
6 years after it was planted : 7 feet,
so x=6 and y = 7
9 years after it was planted: 16 feet
so x= 9 y=16
With thay we can conclude that in 3 years , the tree grew 9 feet. To discover how much the tree grow each year we just nee to divide 9 feet by 3 years which is 3 feet every year.
To write the equatopn now we just need to find the y-intercept which we can discover by setting x to 0:
If in 6 years after the tree was planted it is 7 feet long , we can discover how long it was when it was planted by subtracting 6 years of growth (The slope ) which is 3
7 - 6(years)×3(feet the tree grow each year)
7 - 18 = -11
The tree was -11 feet long when it was planted
which is our y-intercept
( I know it doesnt make sense , but if you apply to a graph it will make more sense )
Now we can make the equation
y = 3x -11
Answer:
and?
Step-by-step explanation:
Answer:
6x +4 where x is amount for standard call
Step-by-step explanation:
A=s^2 50=S^2 s= sqrt50 s=7.071 ms a^2+a^2=c^2 50+50=c^2 100=c^2 c= sqrt100 c=10ms So the answer would be 10 hope this helped
