2 (1/4)= 2.25*100= 225%
the answer to the question is a.
Answer:
26
Step-by-step explanation:
12-8=4
3(4)=12
12/2=6
6*5=30
30-4
26
Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.
Answer:
okay i will pick one red one and i hope this helps lol
Step-by-step explanation:
A = pi * r^2
<span>A = 3.14 * 50^2 </span>
<span>A = 7,850 square miles (area of the 50 mile broadcast signal)
A = pi * r^2
A = 3.14 * 75^2
A = </span>17,662.5 = 17,663 square miles (area of the 75 mile relayed signal)
Now we just need to subtract the 50 mile signal from the 75 mile signal, so:
17,663 - 7,850 = <span>9,813 square miles greater
Hope this helps :)
</span>
