The answer is 
How do I start a concat function and use the Index function with the first arguments list as the text1 argument?
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Answer:
The answer depends on x.value
Step-by-step explanation:
I. It's linear equation
y = mx + b
when y is output, x is input, m is slope and b is addition
So if x = -1
y = -4/3(-1) - 2
= 4/3 - 2
= (4-6)/3
y = -2/3
It will be something like this (-1, -2/3) when -1 is x.value, -2/3 is y.value
You can given x.value be anything like 0, 1, 2, 3 the graph will be like this
(Picture is only example)
