<span>30 hours
For this problem, going to assume that the actual flow rate for both pipes is constant for the entire duration of either filling or emptying the pool. The pipe to fill the pool I'll consider to have a value of 1/12 while the drain that empties the pool will have a value of 1/20. With those values, the equation that expresses how many hour it will take to fill the pool while the drain is open becomes:
X(1/12 - 1/20) = 1
Now solve for X
X(5/60 - 3/60) = 1
X(2/60) = 1
X(1/30) = 1
X/30 = 1
X = 30
To check the answer, let's see how much water would have been added over 30 hours.
30/12 = 2.5
So 2 and a half pools worth of water would have been added. Now how much would be removed?
30/20 = 1.5
And 1 and half pools worth would have been removed. So the amount left in the pool is
2.5 - 1.5 = 1
And that's exactly the amount needed.</span>
You find out how many times 4 goes into 4 and get 1 then you find out how many times 4 goes into 5 and get 1 but you subtract 5 minus 4 and get 1 then bring down the 7 to get 17 then find out how many times 4 goes into 17 which is 4 times because 4 times 4 is 16 and you do 17 minus 16 and get 1 then add a decimal and bring down the 1 to get 10 then find out how many times 4 goes into 10 and get 2 subtract and get 2 bring down the zero turn it into 0 then you get 20 then find out how many times 4 goes into 20 and get 5 and 4*5=20 so 20-20 is 0 so your answer is 114.25
That answer I C. I hope this helps!!!!
1.5 cups
Step-by-step explanation:
3x2=6
4 goes into 6 once and leaves 2 which is half of 4
There is no square root of five...
