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3 years ago

Find the LCD? P+3/p^2+7p+10 and p/5/p^2+5p+6

1 answer:

6 0

P²+7p+10=(p+2)(p+5) and p²+5p+6=(p+2)(p+3) so the LCD is (p+2)(p+3)(p+5).
The first fraction becomes (p+3)²/((p+2)(p+3)(p+5)) and the second fraction becomes p(p+5)/(5(p+2)(p+3)(p+5)).

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In a right triangle, the hypotenuse is three inches more than twice the length of one leg. If the other leg is 12 inches, what i

andrew-mc [135]

Answer:

Length of hypothenuse = 13 inches

Length of other leg = 5 inches

Step-by-step explanation:

A triangle has three sides and three angles. A right angle triangle has 90 degrees as one of the angles. The remaining two angles are complimentary. This means that the sum if the other two angles is 90 degrees.

The longest side is the hypotenuse. The shorter sides are the opposite and adjacent.

In this triangle, the hypotenuse is three inches more than twice the length of one leg. Let the length of one leg be x inches.

Hypothenuse = 2x + 3

The other leg is 12 inches.

The diagram is illustrated in the attached photo.

Applying Pythagoras theorem,

Hypothenuse ^2 = adjacent^2 + opposite ^2

(2x+3)^2 = 12^2 + x^2

(2x+3)(2x+3)= 144 + x^2

4x^2 + 6x + 6x + 9 = 144 + x^2

4x^2 - x^2 + 6x + 6x + 9 - 144 = 0

3x^2 +12x - 135 = 0

3x^2 +27x - 15x - 135 = 0

3x(x+9)-15(x+9)=0

(3x -15)(x+9) = 0

3x -15 = 0 or x+9= 0

3x = 15 or x = -9

x = 15/3 = 5

x = 5inches because it cannot be negative.

Length of hypothenuse = 2x + 3

= 2×5 + 3 = 10 + 3 = 13 inches

6 0

3 years ago

Suppose a triangle has sides a, b, and c, and let theta be opposite the side of length a. If cos theta < 0, what must be true

katrin2010 [14]

If $\cos \theta\ \textless \ 0$ , then angle $\theta$ is obtuse and triangle with sides a, b, c is obtuse triangle.
In an arbitrary triangle can be only one obtuse angle, and the side which lies opposite to the largest angle is the largest. Then since <span>angle $\theta$ is opposite the side of length a</span> you can conclude that a>c and a>b.

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3 years ago

I need some help please

Diano4ka-milaya [45]

What’s your question

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3 years ago

Seorang ayah memberikan sebuah tantangan kepada anaknya untuk i menghitung jumlah uang koin yang diperlukan untuk memenuhi papan

VashaNatasha [74]

The total number of coins required to fill all the $64$ boxes are $\boxed{\bf 18446744073709551615}$ .

Further explanation:

In a chessboard there are $64$ boxes.

The objective is to determine the total number of coins required to fill the $64$ boxes in chessboard.

In the question it is given that in the first box there is $1$ coin, in the second box there are $2$ coins, in the third box there are $8$ coins and it continues so on.

A sequence is formed for the number of coins in different boxes.

The sequence formed for the number of coins in different boxes is as follows:

$\boxed{1,2,4,8,...}$

The above sequence can also be represented as shown below,

$\boxed{2^{0},2^{1},2^{2},2^{3},...}$

It is observed that the above sequence is a geometric sequence.

A geometric sequence is a sequence in which the common ratio between each successive term and the previous term are equal.

The common ratio $(r)$ for the sequence is calculated as follows:

$\begin{aligned}r&=\dfrac{2^{1}}{2^{0}}\\&=2\end{aligned}$

The $n^{th}$ term of a geometric sequence is expressed as follows:

$\boxed{a_{n}=ar^{n-1}}$

In the above equation $a$ is the first term of the sequence and $r$ is the common ratio.

The value of $a$ and $r$ is as follows:

$\boxed{\begin{aligned}a&=1\\r&=2\end{aligned}}$

Since, the total number of boxes are $64$ so, the total number of terms in the sequence is $64$ .

To obtain the number of coins which are required to fill the $64$ boxes we need to find the sum of sequence formed as above.

The sum of $n$ terms of a geometric sequence is calculated as follows:

$\boxed{S_{n}=a\left(\dfrac{r^{n}-1}{r-1}\right)}$

To obtain the sum of the sequence substitute $64$ for $n$ , $1$ for $a$ and $2$ for $r$ in the above equation.

$\begin{aligned}S_{n}&=1\left(\dfrac{2^{64}-1}{2-1}\right)\\&=\dfrac{18446744073709551616-1}{1}\\&=18446744073709551615\end{aligned}$

Therefore, the total number of coins required to fill all the $64$ boxes are $\boxed{\bf 18446744073709551615}$ .

Learn more:

1. A problem on greatest integer function brainly.com/question/8243712

2. A problem to find radius and center of circle brainly.com/question/9510228

3. A problem to determine intercepts of a line brainly.com/question/1332667

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Sequence

Keywords: Series, sequence, logic, groups, next term, successive term, mathematics, critical thinking, numbers, addition, subtraction, pattern, rule., geometric sequence, common ratio, nth term.

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3 years ago

Jamie wants to make a playlist with 8 songs on her iPod. She has 50 songs to choose from, including 15 songs from Maroon 5. Jani

Semmy [17]

So she has 45 songs

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