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4 years ago

5

I’m confused on this one

1 answer:

Alex787 [66]3 years ago

5 0

Triangle ABC is a right triangle, so you can use the Pythagorean Theorem to find diameter AC. 6^2 + 8^2 = x^2. Solve for x to get x = 10. The circumference equation is pi * d, where d is the diameter. So, the answer is 10 pi.

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$3 marked up by 72% <br><br> SHOW YOUR WORK!!!!!!!

cestrela7 [59]

Not sure what answer you are looking for here so i did all of them. you’re welcome

Price = Cost / (1 – (Gross Margin/100%))

Gross Profit (Dollars) = Price x (Gross Margin/100%)

Markup = (Price / Cost) x 100%

Put it together and the

price answer is $10.71

Gross Profit $7.71

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3 0

3 years ago

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Solve for x: 5x +1(3x + 6) > 14

Rom4ik [11]

Answer:

5x+3x+6>14

8x>14-6

8x>8

divide both sides by 8

x>1

8 0

3 years ago

Find the absolute maximum and absolute minimum values of f on the given interval.

anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

$f(x)=xe^{-\frac{x^{2}}{32} }$ , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.

<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

$f(x)=xe^{-\frac{x^{2}}{32} }$

Using the product rule, first derivative will be:

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$

$f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )$ = 0

$1-\frac{x^{2}}{16}=0$

$\frac{x^{2}}{16}=1$

$x^{2}=16$

x = ±4

x can't be -4 because it is not in the interval [-2,8].

$f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76$

$f(4)=4e^{-\frac{4^{2}}{32} }=2.42$

$f(8)=8e^{-\frac{8^{2}}{32} }=1.08$

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0

3 years ago

If the discount rate is 20%, how much would the discount be on a pair of boots that cost $75?

sergejj [24]

20% of off $75 is $60.

3 0

3 years ago

HEY HERE IS THE NEXT QUESTION

mezya [45]

Answer:

5x-0=25

Step-by-step explanation:

5x-0=25

5x=25

x=5

I hope I did this right :/

8 0

3 years ago

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