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34kurt
3 years ago
7

Molly opened a bank account. She deposited $86.50 into her account every month for 20 months. She used $24.50 every month to pay

for singing lessons. After 20 months, she used 1 over 4 of the total money left in her account to go to a summer camp for singers. What is the total amount of money Molly spent to go to the summer camp?
Mathematics
1 answer:
AveGali [126]3 years ago
4 0

Answer:$310

Step-by-step explanation:

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Length of shorter piece is 13 ft

Length of longer piece is 61 - 13 => 48 ft

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3 years ago
The triangles below are similar find the value of x...help I’m stuck
Sergeu [11.5K]
Well, since it is multiple choice, you can just eliminate the answers. If you take 5/4 it equals 1.25. Then you go through the choices. All of the numbers, except 7.2 (C) are infinite. And, 7.2 gives you the 1.25 from before... which is your answer
If this helped, brainliest would be great! Only need one more to level up :)
7 0
3 years ago
Factorise 9w² - 100<br><br><br>​
ohaa [14]

Answer:

9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10).

Step-by-step explanation:

Fact:

\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}.

In other words, (a^{2} - b^{2}), the difference of two squares in the form a^{2} and b^{2}, could be factorized into (a - b)\, (a + b).

In this question, the expression (9\, w^{2} - 100) is the difference between two terms: 9\, w^{2} and 100.

  • 9\, w^{2} is the square of 3\, w. That is: (3\, w)^{2} = 9\, w^{2}.
  • On the other hand, 10^{2} = 100.

Hence:

9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}.

Apply the fact that a^{2} - b^{2} = (a - b) \, (a + b) to factorize this expression. (In this case, a = 3\, w whereas b = 10.)

\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}.

8 0
3 years ago
I will give u 30 points if u help me
nalin [4]
Hope it helps :)
Have a good day :))

5 0
3 years ago
Find the values of the missing sides in the parallelogram given.
natta225 [31]

Given:

m∠B = 44°

Let's find the following measures:

m∠A, m∠BCD, m∠CDE

We have:

• m∠A:

Angle A and Angle B are interior angles on same side of a transversal.

The interior angles are supplementary.

Supplementary angles sum up to 180 degrees

Therefore, we have:

m∠A + m∠B = 180

m∠A + 44 = 180

Subtract 44 from both sides:

m∠A + 44 - 44 = 180 - 44

m∠A = 136°

• m,∠,BCD:

m∠BCD = m∠A

Thus, we have:

m∠BCD = 136°

• m∠CDE:

Angle C and angle CDE form a linear pair.

Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.

Thus, we have:

m∠D = m∠B

m∠D = 44°

m∠CDE + m∠D = 180

m∠CDE + 44 = 180

Subract 44 from both sides:

m∠CDE + 44 - 44 = 180 - 44

m∠CDE = 136°

ANSWER:

• m∠A = 136°

,

•

,

• m∠BCD = 136°

,

•

,

• m∠CDE = 136°

6 0
1 year ago
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