Answer:(a=5,b=3)
7a-3b = 26--------(1)
a + 2b =11---------(2)
on mutlplying by7 in eq 2
= 7a+14b=77-------(3)
from eq(1) and (3) (on substracting)
7a+14b=77
7a-3b=26
________
=-17b=51
b=51/17
b=3
on putting value of b in eq 1
7a-3b = 26
=7a-9=26
7a=35
a=5
Step-by-step explanation:
hope it helps
mark me brainliest
Answer:
Yes
Step-by-step explanation:
A rational number can be expressed as a quotient of two integers. Therefore 78/10 = 39/5 = 0.78 represents a rational number between 7.7 and 7.9. Answer: 39/5
Answer:
B
Step-by-step explanation:
I would say B because they're only 2 options head and tails.
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Answer:
a) dx/dt = kx*(M - h/k - x)
Step-by-step explanation:
Given:
- The harvest differential Equation is:
dx/dt = kx*(M-x)
Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In other words we harvest hx per unit of time for some h > 0
Find:
a) Construct the differential equation.
b) Show that if kM > h, then the equation is still logistic.
c) What happens when kM < h?
Solution:
- The logistic equation with harvesting that is proportional to population is:
dx/dt = kx*(M-x) hx
It can be simplified to:
dx/dt = kx*(M - h/k - x)
- If kM > h, then we can introduce M_n=M -h/k >0, so that:
dx/dt = kx*(M_n - x)
Hence, This equation is logistic because M_n >0
- If kM < h, then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n - x) < 0 for all x<0 then the population will tend to zero for all initial conditions
