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alexira [117]
3 years ago
15

Which expression can be used to determine the length of segment AB?

Mathematics
2 answers:
AleksandrR [38]3 years ago
5 0

Answer:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

Given segment AB and point A with coordinates (x₁,y₁) and point B(x₂,y₂) as end points in the segment, the distance between the points forms the length of the segment AB and can be determined by the expression;

d=√ (x₂-x₁)² + (y₂-y₁)²

Stells [14]3 years ago
3 0

Answer:

you need to provide a picture friend

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Savatey [412]

Answer:

6/12 and 4/8

Step-by-step explanation:

2/4 = 1/2

___________________

6/8 not equal to 1/2

6/12 = 1/2

4/8 = 1/2

4/6 does not equal to 1/2

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7 0
3 years ago
Complete the solution of the equation. find the value of y when equals 2. -3x-8y=10
Afina-wow [57]
The value of y can be calculated by translating the equation such that we solve y in terms of x.

                            -3x - 8y = 10
 
                               -8y = 10 + 3x
 
                               y = (10 + 3x) / -8

Then, we substitute 2 to the x in the equation.

                             y = (10 + 3(2)) / - 8  = 16/-8

                                y = -2 

Thus, the value of y in the equation is -2. 
4 0
3 years ago
Robert can paint a certain wall in 4 minutes, while it takes Jack 12 minutes to paint the same wall. How long will it take Rober
olga_2 [115]
It will take 24 minutes.
this is because the lowest common multiple is 24.

hope this helps you
3 0
3 years ago
Please help me I can't do this answer
Tomtit [17]

Answer:

Its option number 2 perhaps, sorry if im wrong

Step-by-step explanation:

6 0
3 years ago
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v>=2i-4tj^
guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj  .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j

B )

Acceleration a is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j

Hence , this is the required solution .

5 0
3 years ago
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