The temperature of the water getting colder would cause the liquid in the thermometer to drop due to less heat being transferred from the water to the liquid, so the liquid molecules are closer than when they have high energy.
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The total thermal power generated by this plutonium source is determined as 5.65 J/s.
<h3>Total thermal power generated</h3>
The total thermal power generated by this plutonium source is determined as follows;
ΔP = Eλ
where;
- E is the energy of the particles = 5.6 mev
- λ is the activity of the plutonium, which should be = 6.3 x 10¹⁵ s⁻¹
ΔP = (5.6 mev) x (6.3 x 10¹⁵ s⁻¹)
ΔP = (5.6 x 10³ x 1.6 x 10⁻¹⁹ J) x (6.3 x 10¹⁵ s⁻¹)
ΔP = 5.65 J/s
Learn more about thermal power here: brainly.com/question/7541718
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Answer:
speed =distance/time taken
5 m/s