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IrinaK [193]
3 years ago
5

Often what one expects to see influences what is perceived in the surrounding environment. Please select the best answer from th

e choices provided T F
Physics
2 answers:
Stella [2.4K]3 years ago
8 0
Hello <span>Andijwiltbank 
</span>

Question: <span>Often what one expects to see influences what is perceived in the surrounding environment. True or False?

Answer: True

Reason: What we observe about the environment decides what we believe about it and how we react.


Hope This Helps :-)
-Chris</span>
prohojiy [21]3 years ago
5 0

This statement is in-doubtingly true

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What is the difference between cytology and histology
bulgar [2K]

Explanation:

what is the difference between cytology and histology

Histology involves the study of tissue and Cytology involves the study of cells, both of which are derived from various organs of the human body. The Histology laboratory is responsible for the preparation of tissue for diagnosis by Pathologists.

8 0
3 years ago
What is the inverse square law and how does it relate to gravity?
Nesterboy [21]

Answer:

Inverse Square Law Newton proposed the Inverse Square Law. The effect of gravity (and also on forces such as sunlight) works like this. If say we have a half-mass Earth, it would produce a gravity of not half but a quarter (the square of 2).

7 0
4 years ago
The brightness of a star depends on what
Zinaida [17]
It’s D size and temperature
7 0
3 years ago
Ellus
Lesechka [4]

Answer:

W'=125.44 N

Explanation:

The weight of a person on the surface of Earth is 784 N

Weight is given by :

W = mg

m is mass of the person and g is acceleration due to gravity on the surface of Earth (10 m/s²)

m=\dfrac{W}{g}\\\\m=\dfrac{784}{10}\\\\m=78.4\ kg

The acceleration due to gravity on the surface of Moon, g' = 1.6 m/s²

Weight of the person on the moon is :

W'=mg'

W'=78.4\ kg\times 1.6\ m/s^2\\\\W'=125.44\ N

Hence, the person would weigh 125.44 N on the Moon.

6 0
3 years ago
I need the answer asap plz!!
Vesnalui [34]

Answer:

266.7k

Explanation:

Given parameters:

Initial pressure  = 36Pa

Initial temperature  = 300k

New pressure  = 32Pa

Unknown:

New temperature  = ?

Solution:

To solve this problem, we have to apply the combined gas law when the volume is constant;

in this instant, when the volume is constant, the pressure of a given mass of gas varies directly with the absolute temperature.

          \frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }  

P and T are pressure and temperature

1 and 2 are initial and final states

  Insert the parameters and solve;

       \frac{36}{300}   = \frac{32}{T_{2} }  

      T₂  = 266.7k

7 0
3 years ago
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