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olga55 [171]
3 years ago
11

Why did earth most likely form into distinct, separate layers? (HELP ASAP PLZ)

Physics
2 answers:
g100num [7]3 years ago
8 0

Answer:

C

Explanation:

Rocks with hotter temperatures sank to the bottom of the Earth. The rocks with the hottest temperature became the core and the rocks with the least amount of heat became the crust.

Hope this helps!

Damm [24]3 years ago
4 0

Answer:

The stratification of Earth into its geologic layers was brought about by the formation of the Earth's iron core. The iron core was generated by a combination of radioactive decay and gravitation, which raised the temperature enough for molten iron to form. The migration of molten iron to the center of the Earth displaced the less dense materials toward the surface.The early Earth needed lots of energy to trigger the creation of molten iron. Some of this energy came from radioactive decay. Radioactive elements such as uranium and thorium give off heat when they decay. Radioactive elements were present in greater amounts in the early Earth. The radiation emitted by these elements increased the temperature of the Earth by roughly 2,000 degrees Celsius (about 3,600 degrees Fahrenheit).Gravitational forces both helped the iron accumulate in the center of the Earth and helped generate additional temperature. As the early Earth compacted into a planet thanks to gravity, this compaction gave off heat. As a result, gravitational energy helped raise the temperature of the Earth by an additional 1,000 degrees Celsius (about 1,800 degrees Fahrenheit). In turn, this temperature increase helped sustain the presence of molten iron at the Earth's core.

Explanation:

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Lady bird [3.3K]

Answer:

Explanation:

a)

Using Ohms Law

R= \rho \frac{l}{\pi a^2 }
\\V = IR = E l = I \rho \frac{l}{\pi a^2 }
\\E = \frac{I \rho}{\pi a^2 }
\\E = J \rho


Where J is the current density J = \frac{I}{\pi a^2 }


and the direction of E is the same as the direction of the current. Since J is uniform throughout the conductor E = \rhoJ just inside at a radius a (and anywhere else).

b)

Since we have no changing electric fields we can use Ampere’s law in it’s simplest form without displacement current

\oint B .dl = B 2 \pi a = \mu_{o} I


such that

B = \frac{\mu_{o} I}{2 \pi a }


and by the right hand rule, since the current is going to the right, the magnetic field is circling around the conductor such that it’s pointing out of the page at the top and into the page at the bottom.

c)

The Poynting vector is given by

S = \frac{1}{ \mu_o} |E \textrm{x}B| = \frac{\rho I^2}{2 \pi^2 a^3}


and by the right hand rule it’s always pointing in towards the center of the conductor.

d)

Note: directions of these three vectors are mentioned along with their magnitudes in above 3 parts a , b and c

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3 years ago
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torisob [31]

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7 0
4 years ago
What is the net work on the block?
Strike441 [17]

Answer:

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8 0
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ehidna [41]
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d1i1m1o1n [39]

Answer:

Explanation:

for earth -sun system

E = σ T⁴ ,  E is radiation emitted by sun at temperature T

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