Explanation:
It is given that,
Wavelength of red light,
Power of the laser,
(a) The energy carried by each photon is given by :
(b) Let n is the number of photons emitted by the laser per second. It can be calculated as :
Hence, this is the required solution.
Answer:
0.03605 V/m is the electric field in the gold wire.
Explanation:
Resistivity of the gold =
Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)
Diameter of the wire = d = 0.9 mm
Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm =
( 1mm = 0.001 m)
Area of the cross-section =
Resistance of the wire = R
Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)
( Ohm's law)
We know, Electric field is given by :
0.03605 V/m is the electric field in the gold wire.