Question

A mixture of gases contains 1.50 mol of o2, 0.75 mol of he, and 2.25 mol of n2. the total pressure exerted by the mixture is equal to 2.50 atm. what is the partial pressure of the he?

Answer 1

A mixture of gases contains 1.50 mol of o2, 0.75 mol of he, and 2.25 mol of n2. the total pressure exerted by the mixture is equal to 2.50 atm .The partial pressure of the he will be 4.167 atm .

Each constituent gas in a mixture of gases has a partial pressure which is the notional pressure of that constituent gas if it alone occupied the whole volume of the original mixture at the same temperature.

given

moles of O2 = 1.50 moles

moles of He = 0.75 moles

moles of N2 = 2.25 moles

total moles = 1.50 + 0.75 + 2.25 = 4.50 moles

total pressure exerted by the mixture is =  2.50 atm

partial pressure of He = (moles of He / Total moles) * total pressure

                                     = (0.75 / 4.50) * 25 = 4.167 atm

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