Suppose a piece of dust finds itself on a CD. If the spin rate of the CD is 500 rpm, and the piece of dust is 4.3 cm from the ce
1 answer:
You might be interested in
Answer:
gravitational force acting on the piano (piano's weight)
force of Chadwick on the piano
force of the floor on the piano (normal force)
Explanation:
Figure is missing: found it in attachment.
In the figure, we notice that the piano is accelerating along the horizontal direction: this means that there is a net force acting along this direction. This force is prodiced by Chadwick, and it acts in the same direction as the acceleration, so one force is:
force of Chadwick on the piano
Also, every object on Earth experencies the force of gravity, which is also called weight. The weight of the piano acts downward, so a second force is:
gravitational force acting on the piano (piano's weight)
Finally, we notice that the piano is in equilibrium along the vertical direction (no acceleration): this is because there is another force acting opposite to the piano's weight (and with equal magnitude), and this force is the normal force exerted by the floor on the piano:
force of the floor on the piano (normal force)
Answer:
All the three rocks will hit the ground with same speed.
Explanation:
For rocks X and Z, motion is along a straight line but in case of rock Y, motion is two dimensional. Since velocity is a vector it will be difficult for us to calculate the final velocity in each case. So we should find a way to solve this problems using a scalar which is related to velocity. The best and easy to use scalar related to velocity is kinetic energy. Since there is no air resistance, the total mechanical energy of the stone remains the same. Therefore we can use the concept of conservation of mechanical energy to solve this problem.
i.e. initial mechanical energy = final mechanical energy
let us take the edge of the cliff as initial position and ground as the final position.
We know that
Mechanical energy = Kinetic energy + Potential energy
Initial Mechanical energy = Initial Kinetic energy + Initial Potential energy
we know that
Potential energy = mgh
where,
m = mass of the body
g = acceleration due to gravity
h = height from ground
All the three rocks are identical and are thrown from same height. Therefore m and h are same for all the three which implies that the initial potential energy for all the three rocks is same.
Similarly, we know that
Kinetic energy =
where,
m = mass of the body
v = velocity of the body
Since all the rocks are thrown with same speed, v is same for all the rocks. Thus initial kinetic energy is also same for all.
Since initial kinetic energy and Initial Potential energy is same for all the three, Initial Mechanical energy is also same for them.
Next let us consider the final position. At the ground h = 0. Therefore final potential energy of all the three rocks is 0. Thus they will be having only kinetic energy.
By conservation of mechanical energy,
initial mechanical energy = final mechanical energy
i.e. Initial Kinetic energy + Initial Potential energy = final Kinetic energy + final Potential energy
final potential energy = 0
thus,
Initial Mechanical energy = Initial Kinetic energy + Initial Potential energy = final Kinetic energy
Initial Mechanical energy = final Kinetic energy
Since Initial Mechanical energy is same for all the three, by the above equation final Kinetic energy is also same for all the three. Since here, kinetic energy is the function of only velocity, final velocity is also same for all the three rocks.
i.e. all the three rocks will hit the ground with same speed.